Kim caught a fish that was 9/10 of a meter long. Doug caught a fish that was 2/3 as long as Kim's fish. So, Doug caught a fish that was 3/5 meters long.
<h3>What is the fundamental principle of multiplication?</h3>
If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways
Kim caught a fish that was 9/10 of a meter long. Doug caught a fish that was 2/3 as long as Kim's fish.
Kim caught a fish of length = 9/10 m
Doug caught a fish of length = 2/3 as long as Kim's fish.
= 2/3 x 9/10
= 18 / 30
= 3/5
Thus, Doug caught a fish that was 3/5 meters long.
Learn more about multiplications;
brainly.com/question/14059007
Answer:
Step-by-step explanation:
In ΔMOT and ΔMPR,
OT║PR and MR is a transverse,
Therefore, ∠MTO ≅ ∠MRP [Corresponding angles]
Similarly, OT║PR and MP is a transverse,
Therefore, ∠MOT ≅ ∠MPR [Corresponding angles]
ΔMOT ~ ΔMPR → [By AA postulate of similarity]
[Reason → Corresponding sides of the similar triangles are proportional]
[By segment addition postulate]
1 +
= 1 + ![\frac{TR}{MT}](https://tex.z-dn.net/?f=%5Cfrac%7BTR%7D%7BMT%7D)
![\frac{OP}{MO}=\frac{TR}{MT}](https://tex.z-dn.net/?f=%5Cfrac%7BOP%7D%7BMO%7D%3D%5Cfrac%7BTR%7D%7BMT%7D)
In ΔTSR,
∠1 ≅ ∠2 [Given]
Therefore, TR ≅ SR [Sides opposite to the equal angles in a triangle are equal]
Therefore, ![\frac{OP}{MO}=\frac{SR}{MT}](https://tex.z-dn.net/?f=%5Cfrac%7BOP%7D%7BMO%7D%3D%5Cfrac%7BSR%7D%7BMT%7D)
Or ![\frac{MO}{OP}=\frac{MT}{SR}](https://tex.z-dn.net/?f=%5Cfrac%7BMO%7D%7BOP%7D%3D%5Cfrac%7BMT%7D%7BSR%7D)
Hence proved.
Answer:
Part A: 8 meters
Part B: B, D
Step-by-step explanation:
Here’s the correct answer, how I got it, how to help for next time, and the equation graphed :)
Answer:
D
Step-by-step explanation:
y2 is the y to the right, and -6 is to the right of -8 on the x-axis, so (x2, y2) = (-6,52). plug in the values and you get (52-48)/(-6--8), which equals 4/2, which simplifies to 2.