Use the following to calculate H°lattice of MgF2. Mg(s) Mg(g) H° = 148 kJ F2(g) 2 F(g) H° = 159 kJ Mg(g) Mg+(g) + e- H° = 738 kJ
Mg+(g) Mg+2(g) + e- H° = 1450 kJ F(g) + e- F -(g) H° = -328 kJ Mg(s) + F2(g) MgF2(s) H° = -1123 kJ kJ/mol
1 answer:
Answer:
The correct answer is -2952 KJ/mol
Explanation:
Attached is the diagram for Born- Haber cycle. According to the cycle:
ΔHf= ΔH1 + ΔH2 + ΔH3 + ΔH4 + ΔH5 + LE
In order to calculate the lattice energy (LE):
LE= ΔHf - ΔH1 - ΔH2 - ΔH3 - ΔH4 - ΔH5
LE= -1123 KJ/mol - 148 KJ/mol - 159 KJ/mol - 728 KJ/mol - 1450 KJ/mol - (2 x (-328 KJ/mol)
LE= -2952 KJ/mol
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