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leonid [27]
4 years ago
8

Use the following to calculate H°lattice of MgF2. Mg(s) Mg(g) H° = 148 kJ F2(g) 2 F(g) H° = 159 kJ Mg(g) Mg+(g) + e- H° = 738 kJ

Mg+(g) Mg+2(g) + e- H° = 1450 kJ F(g) + e- F -(g) H° = -328 kJ Mg(s) + F2(g) MgF2(s) H° = -1123 kJ kJ/mol

Chemistry
1 answer:
aev [14]4 years ago
8 0

Answer:

The correct answer is -2952 KJ/mol

Explanation:

Attached is the diagram for Born- Haber cycle. According to the cycle:

ΔHf= ΔH1 + ΔH2 +  ΔH3 + ΔH4 + ΔH5 + LE

In order to calculate the lattice energy (LE):

LE= ΔHf - ΔH1 - ΔH2 -  ΔH3 - ΔH4 - ΔH5

LE= -1123 KJ/mol - 148 KJ/mol -  159 KJ/mol - 728 KJ/mol - 1450 KJ/mol - (2 x (-328 KJ/mol)

LE= -2952 KJ/mol

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Answer:

The answer is the explanation.

Explanation:

The acetic acid, CH3COOH, reacts with calcium hydroxide, Ca(OH)2, producing acetate ion, CH3COO- and water as follows:

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