Answer:
This is called negative adsorption. Hence if the concentration of the adsorbate is less on the surface of the adsorbent than in the bulk, it is known as negative adsorption.
Explanation:
Hope this helps
Answer:
Chemical bonds are how atoms, and even molecules join together.
Explanation:
There are two main types of primary chemical bonds. While secondary links relate to molecules, primary ties are atom to atom. This answer explains basic primary bonds only.
One must comprehend what a valence shell is before I proceed. The outer electron orbital of an atom is known as the valence shell. Most of the time (except from hydrogen), atoms desire to have 8 electrons in their valence shell, thus they form bonds with other atoms to accomplish this.
<em>All bonds result in a new chemically different molecule. Now, the two types are:</em>
- Covalent: When two atoms combine their electrons to fill their valence shells. The atoms are joined together by this "sharing."
- Ionic: When one atom <em>transfers</em> an electron to another atom in order to fulfill the valence electron requirement. Because electrons have a negative charge, the atom that <em>produced </em>them gains a positive charge as a result of losing its negative charge. The atom that received the electron therefore acquires a negative charge. Because opposing charges attract, it seems sense that the charged atoms bind as a result.
Answer:
the type of drink they consumed each day
The molar mass of a, b and c at STP is calculated as below
At STP T is always= 273 Kelvin and ,P= 1.0 atm
by use of ideal gas equation that is PV =nRT
n(number of moles) = mass/molar mass therefore replace n in the ideal gas equation
that is Pv = (mass/molar mass)RT
multiply both side by molar mass and then divide by Pv to make molar mass the subject of the formula
that is molar mass = (mass x RT)/ PV
density is always = mass/volume
therefore by replacing mass/volume in the equation by density the equation
molar mass=( density xRT)/P where R = 0.082 L.atm/mol.K
the molar mass for a
= (1.25 g/l x0.082 L.atm/mol.k x273k)/1.0atm = 28g/mol
the molar mass of b
=(2.86g/l x0.082L.atm/mol.k x273 k) /1.0 atm = 64 g/mol
the molar mass of c
=0.714g/l x0.082 L.atm/mol.K x273 K) 1.0atm= 16 g/mol
therefore the
gas a is nitrogen N2 since 14 x2= 28 g/mol
gas b =SO2 since 32 +(16x2)= 64g/mol
gas c = methaneCH4 since 12+(1x4) = 16 g/mol
Answer:
q = -6464.9 kJ
Explanation:
We are given that the heat of combustion is ∆H° = −394 kJ per mol of carbon.Therefore what we need to do is calculate how many moles of C are in the lump of coal by finding its mass since the density is given.
vol = 5.6 cm x 5.1 cm x 4.6 cm = 131.38 cm³
m = d x v = 1.5 g/cm³ x 131.38 cm³ = 197.06 g
mol C = m/MW = 197.06 g/ 12.01g/mol = 16.41 mol
q = −394 kJ /mol C x 16.41 mol C = -6464.9 kJ
