We can rephrase the statement with a little more specificity in order to understand the answer here.
The mass of the products can never be more than the The mass that is expected.
Answer:
The answer to your question is C = 0.037 cal/g°C
Explanation:
Data
mass of the wire = m = 237 g
temperature 1 = T1 = 25°C
temperature 2 = T2 = 107°C
Heat = Q = 722 cal
Specific heat = C
Process
1.- Write the formula to find the specific heat
Q = mC(T2 - T1)
-Solve for C
C = Q / m(T2 - T1)
2.- Substitution
C = 722 / 237(107 - 25)
3.- Simplification
C = 722 / 237(82)
C = 722 / 19434
4.- Result
C = 0.037 cal/g°C
Answer:
6.0 L
Explanation:
For this question, we can use
P1×V1= P2 × V2
where
P1 (initial pressure)= 0.2 kPa
V1 (initial volume)= 15L
P2 (final pressure)= 0.5 kPa
V2(final volume)= ?
Since we are trying to find final volume, we can rearrange the equation to make V2 the subject.
V2= (P1 × V1)/ P2
V2= (0.2 ×15)/0.5
V2 =6 L
Answer: When an electric current is passed through a substance to effect a chemical change.
