Answer:
Since you are producing 3.6 mol CO2, you can calculate the starting moles of CH4 with the simple mole-to-mole ratio: 1 mol CH4 / 1 mol CO2 as a conversion factor. Taking 3.6 mol CO2 x 1 mol CH4 / 1 mol CO2 = 3.6 mol CH4 (after canceling out the moles of CO2 on the top and bottom of the calculation)
Explanation:
Answer:The correct answer is ;
The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.
Explanation:

In an oxidation recation addition of oxygen atom takes place or loss of electrons takes place.
In an reduction reaction removal of oxygen atom takes place or gain of electrons takes place.
In the given reaction , the nitrogen atom is present in +2 oxidation state in NO molecule and present in 0 oxidation state in
molecule. Hence, nitrogen is getting reduced that is reduction reaction. NO is oxidizing agent
In the given reaction , the carbon atom is present in +2 oxidation state in CO molecule and present in +4 oxidation state in
molecule. Hence ,carbon is getting oxidized that is oxidation reaction. CO is a reducing agent.
Answer:
b,c and d
Explanation:
The following processes are coupled to the dephosphorylation of ATP
b. the endergonic reaction forming gluco-6-phosphate
c. Myosin action during muscle contraction
d. de novo anabolism of nucleotide
Answer:
Sulfur — S
calcium — Ca
carbon — C
silver — Ag
gold — Au
helium — He
hydrogen — H
should become easier for you to memorise them as you go on in life (meaning going up a grade… grade 7 to 8 to 9 to 10 until you reach college and whatnot)