The square root of 1 is 1, but the square root of 18 needs to be explored. 18 is 9*2, and 9 is a perfect square. So let's rewrite our original problem using that fact:
. We can pull out the square root of 1 as 1 and the square root of 9 as 3, leaving the 2 behind:
. And there you go!
You would have to use the slope formula y2-y1/x2-x1 and substitute the values into this. That would be 5+3/6-6 which is 8/0. 0 can’t be in the denominator because no number can be divided by 0 so the slope is undefined.
Answer:
t = 2, t = 3, t = 4, and t = 6.
Step-by-step explanation:
So, we can plug in each t value into the equation to see if it is correct.
9(2) ≤ 107
18 ≤ 107
This is correct because the equation is looking for something that is less than or equal to 107.
9(3) ≤ 107
27 ≤ 107
Same reason as stated above.
9(4) ≤ 107
36 ≤ 107
Same reason as stated above.
9(6) ≤ 107
54 ≤ 107
Same reason as stated above.
Therefore, t = 2, t = 3, t = 4, and t = 6 are all solutions to the inequality.
Answer:
1. 0.33 2. 0.16 3. o.11
Step-by-step explanation: