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Crazy boy [7]
3 years ago
11

5 cosas electricas que usan los zapateros los mecanicos y los electricistas ayuda plis rapido

Chemistry
1 answer:
IgorLugansk [536]3 years ago
4 0
Destornilladores, alicates de corte diagonal, alicates de punta fina, alicates de bomba ajustable y cinta métrica con punta magnética
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69. Sequencing Arrange these hydrates in order of
Kobotan [32]

In order of  increasing percent water content:CoCl₂.6H₂O, Ba(OH)₂.8H₂O, MgSO₄.7H₂O

<h3>Further explanation</h3>

\tt \%element=\dfrac{Ar~element}{MW~compound}\times 100\%

CoCl₂.6H₂O.MW=237.90 g/mol

6H₂O MW = 6.18=108 g/mol

\tt \%H_2O=\dfrac{108}{237.9}\times 100\%=45.4\%

MgSO₄.7H₂O.MW=246.48 g/mol

MW 7H₂O = 7.18=126 g/mol

\tt \%H_2O=\dfrac{126}{246.48}\times 100\%=51.1\%

Ba(OH)₂.8H₂O MW=315.48 g/mol

MW 8H₂O = 8.18=144 g/mol

\tt \%H_2O=\dfrac{144}{315.48}\times 100\%=45.6\%

4 0
3 years ago
Which of the following is NOT true of a chemical reaction. PLZ HELP ASAP
valentina_108 [34]

Answer:

if you want to have answers, don't take it wrong ...but put more details !

Explanation:

3 0
3 years ago
Read 2 more answers
How many molecules of glucose are produced by each cycle of the light reaction?
disa [49]
Zero (0) molecules of glucose are produced.
4 0
3 years ago
A tetraphenyl phosphonium chloride (TPPCl) powder (FW=342.39) is 94.0 percent pure. How many grams are needed to prepare 0.45 L
slega [8]

Answer:

5.41 g

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For tetraphenyl phosphonium chloride :

Molarity = 33.0 mM = 0.033 M (As, 1 mM = 0.001 M)

Volume = 0.45 L

Thus, moles of tetraphenyl phosphonium chloride :

Moles=0.033 \times {0.45}\ moles

Moles of TPPCl = 0.01485 moles

Molar mass of TPPCl = 342.39 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.01485\ g= \frac{Mass}{342.39\ g/mol}

Mass of TPPCl = 5.0845 g

Also,

TPPCl is 94.0 % pure.

It means that 94.0 g is present in 100 g of powder

5.0845 g is present in 5.41 g of the powder.

<u>Answer -  5.41 g</u>

5 0
4 years ago
A student decided to research primate psychology for their science project. They measured how long it took gorillas to adapt to
Gwar [14]

Answer: the answer is  D im pretty sure

Explanation:

3 0
3 years ago
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