$\frac{2x^2+5x+3}{x^2-3x-4}$ divided by $\frac{4x^2+2x-6}{x^2-8x+16}$ is the same thing as multiplying $\frac{2x^2+5x+3}{x^2-3x-4}$ by $\frac{x^2-8x+16}{4x^2+2x-6}$ .

The equation we get is:

$\frac{2x^2+5x+3}{x^2-3x-4}*\frac{x^2-8x+16}{4x^2+2x-6}$

With this equation, we can factor each equation:

$\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}$

We can cancel out like terms since they would be dividing each other:

$\frac{x-4}{2x-2}$

8 0

3 years ago

Making art and can help you find a difference 13 - 5

Genrish500 [490]

Answer:

Here's how to solve

Step-by-step explanation:

Okay so 13 -5

What can you add to 5 to get 13?

5+5=10

5+6=11

5+7=12

5+8=13

8 would be your answer.

5 0

2 years ago

A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use in minutes of one part

vovikov84 [41]

The answer is 325 517 424 395 494

4 0

3 years ago

Read 2 more answers

It 5/2 not -5/2 and sorry for telling u the

babunello [35]

What does this mean buddy?

4 0

3 years ago

Read 2 more answers