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3 years ago

Which statement is true?

Physics

2 answers:

Alisiya [41]3 years ago

6 0

This is kind of an awkward situation.

A, B, and C are definitely false:

A ... gasoline is not a renewable resource

B ... hydroelectric dams don't use wind for anything; windmills do

C ... fossil fuels are not renewable resources

So that leaves D, but D is partly absurd too.

Natural gas burning does not produce gases to turn the turbines. Natural gas is burned to produce HEAT, just like on the stove in my kitchen. The heat is used to boil water, and the steam from the boiling water is what turns the turbines to generate electrical energy.

But I guess you gotta pick choice-D as the answer.

djverab [1.8K]3 years ago

4 0

The answer is D. Natural gas can be burned, producing hot gases that turn turbines to generate electricity.

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15. The Energy possessed by a body by virtue of its position or state is called :

shepuryov [24]

Answer:

The Energy possessed by a body by virtue of its position or state is called Potential energy.

Mathematically potential energy can be written as,

Potential energy = mgh

Where 'm' represents mass of the body, 'g' represents gravity of the earth and 'h' represents height of body. Potential energy depends on the height, higher the hight from the surface of the earth, maximum will be the potential energy.

4 0

3 years ago

WILL GIVE BRAINLIEST!

yaroslaw [1]

stable equilibrium, if displaced from equilibrium, it experiences a net force or torque in a direction opposite to the direction of the displacement.

unstable equilibrium, if displaced it experiences a net force or torque in the same direction as the displacement from equilibrium. A system in unstable equilibrium accelerates away from its equilibrium position if displaced even slightly.

neutral equilibrium, is when an equilibrium is independent of displacements from its original position.

Have a good day, hope this helps

8 0

3 years ago

Calculate the mag-netic field (magnitude and direc-tion) at a point p due to a current i=12.0 a in the wire shown in fig. p28.68

creativ13 [48]

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The magnitude is $B= 4.2 *10^ {-6}T$ , the direction is into the page

Explanation:

From the question we are told that

The current is $i = 12.0 A$

The radius of arc bc is $r_{bc} = 30.0 \ cm =\frac{30}{100} = 0.3m$

The radius of arc da is $r_{da} = 20.0 \ cm = \frac{20}{100} = 0.20 \ m$

The length of segment cd and ab is = $l = 10cm = \frac{10}{100} = 0.10 m$

The objective of the solution is to obtain the magnetic field

Generally magnetic due to the current flowing in the arc is mathematically represented as

$B = \frac{\mu_o I}{4 \pi r}$

Here I is the current

$\mu_o$ is the permeability of free space with a value of $4\pi *10^{-7}T \cdot m/A$

r is the distance

Considering Arc da

$B_{da} = \frac{\mu_o I}{4 \pi r_{da}} \theta$

Where $\theta$ is the angle the arc da makes with the center from the diagram its value is $\theta = 120^o = 120^o * \frac{\pi}{180} = \frac{2\pi}{3} rad$

Now substituting values into formula for magnetic field for da

$B_{da} = \frac{4\p *10^{-7} * 12}{4 \pi (0.20)}[\frac{2 \pi}{3} ]$

$= \frac{10^{-7} * 12}{0.20} * [\frac{2 \pi}{3} ]$

$B_{da}= 12.56*10^{-6} T$

Looking at the diagram to obtain the direction of the current and using right hand rule then we would obtain the the direction of magnetic field due to da is into the pages of the paper

Considering Arc bc

$B_{bc} = \frac{\mu_o I}{4 \pi r_{bc}} \theta$

Substituting value

$B_{bc} = \frac{4 \pi *10^{-7} * 12}{4 \pi (0.30)} [\frac{2 \pi}{3} ]$

$B_{bc}= 8.37*10^{-6}T$

Looking at the diagram to obtain the direction of the current and using right hand rule then we would obtain the the direction of magnetic field due to bc is out of the pages of the paper

Since the line joining P to segment bc and da makes angle = 0°

Then the net magnetic field would be

$B = B_{da} - B{bc}$

$= 12.56*10^{-6} - 8.37*10^{-6}$

$= 4.2 *10^ {-6}T$

Since $B_{da} > B_{bc}$ then the direction of the net charge would be into the page

3 0

4 years ago

Can rock undergo compression, tension, and shear stress all at once? explain

Katena32 [7]

This causes reverse faults, which are the reverse of normal faults, because in this case, the hanging wall slides upward relative to the footwall. Shear stress is when rock slabs slide past each other horizontally. There is no vertical movement of either the hanging wall or footwall, and we get a strike-slip fault.

7 0

3 years ago

Can someone help my with my Physics lab pleaseeeee

den301095 [7]

Answer:

whats the question

Explanation:

where your question

4 0

3 years ago