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Zinaida [17]
3 years ago
10

1. What is the primary difference between an ideal emf device and a real emf device? a) The electric potential of a real emf dev

ice is limited. b) The resistance of a real emf device is finite, but the resistance of an ideal emf device is assumed to be infinite. c) A real emf device can carry an electric current, but an ideal emf device does not. d) A real emf device has an internal resistance, but an ideal emf device does not. e) A real emf device has a potential difference across its terminals, but an ideal emf device does not
Physics
1 answer:
Kazeer [188]3 years ago
3 0

Answer:

The answer is option D.

Explanation:

An EMF device is a device that produces an electromagnetic field and the components that it has also have their own internal resistance.

This is the case in a real life EMF device but for an ideal EMF device, the internal resistance is equal to zero so there is no voltage drop because of that.

The answer is option D.

I hope this answer helps.

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What is the relationship between and experiment and a hypothesis
MariettaO [177]

Answer:

an experiment is a way to test a hypothesis. A hypothesis is a prediction. You predict that if you change one thing (the independent variable) the other thing (the dependent variable) will change.

3 0
2 years ago
You are trying to determine the specific gravity of a solid object that floats in water. If m is the mass of your object, mS is
Alisiya [41]

Answer:

Specific Gravity = m/[m(s)-m(os)]

Explanation:

Specific gravity, also called relative density, is the ratio of the density of a substance to the density of a reference substance. By this definition we need to find out the ratio of density of the object of mass m to the density of the surrounding liquid.

m = mass of the object

<u>Weight in air</u>

W (air) = mg, where g is the gravitational acceleration

<u>Weight with submerged with only one mass</u>

m(s)g + Fb = mg + m(b)g, <em>consider this to be equation 1</em>

where Fb is the buoyancy force

Weight with submerged with both masses

m(os)g + Fb’ = mg + m(b)g, <em>consider this to be equation 2</em>

<u>equation 1 – equation 2 would give us</u>

m(s)g – m(os)g = Fb’ – Fb

where Fb = D x V x g, where D is the density of the liquid the object is submerged in, g is the force of gravity and V is the submerged volume of the object

m(s)g – m(os)g = D(l) x V x g

m(s) – m(os) = D(l) x V

we know that Mass = Density x V, which in our case would be, D(b) x V, which also means

V = Mass/D(b), where D(b) is the density of the mass

<u>Substituting V into the above equation we get</u>

m(s) – m(os) = [D(l) x m)/ D(b)]

Rearranging to get the ratio of density of object to the density of liquid

D(b)/D(l) = m/[m(s)-m(os)], where D(b)/D(l) denotes the specific gravity

8 0
3 years ago
Which of the following statements is TRUE for high-visibility clothing? A. High-visibility clothing helps to reduce insect probl
Mazyrski [523]
C. High-visibility clothing is important to wear in areas with moving vehicles
5 0
3 years ago
Read 2 more answers
Monochromatic light falls on two very narrow slits 0.048 mm apart. successive fringes on a screen 5.00 m away are 6.5 cm apart n
atroni [7]
In a double-slit interference experiment, the distance y of the maximum of order m from the center of the observed interference pattern on the screen is
y= \frac{m \lambda D}{d}
where D=5.00 m is the distance of the screen from the slits, and 
d=0.048 mm=0.048 \cdot 10^{-3}m is the distance between the two slits.
The fringes on the screen are 6.5 cm=0.065 m apart from each other, this means that the first maximum (m=1) is located at y=0.065 m from the center of the pattern.
Therefore, from the previous formula we can find the wavelength of the light:
\lambda =  \frac{yd}{mD}= \frac{(0.065 m)(0.048 \cdot 10^{-3}m)}{(1)(5.00 m)}=  6.24 \cdot 10^{-7}m

And from the relationship between frequency and wavelength, c=\lambda f, we can find the frequency of the light:
f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{6.24 \cdot 10^{-7}m}=4.81 \cdot 10^{14}Hz
4 0
3 years ago
21. A fisherman catches two sturgeons. The smaller of the two has a measured length of 93.46 cm (two dec- imal places and four s
Leto [7]

Answer:

135.3 cm + 93.46cm

= 228.76 cm

So total length of two fish is 228.76

5 0
2 years ago
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