1. What is the primary difference between an ideal emf device and a real emf device? a) The electric potential of a real emf dev
1 answer:
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Yes, these two objects have different masses.
<h3>How can we calculate that this statement is right ?</h3>To calculate the precision of mass we are using the formula,
Precision(P) =
Or,m=
-m₁
For the first case we are given,
m₁= The recorded value of mass
= 128.01 g
P= Precision of the mass
=0.005g
So, according to the formula, m will be,
m=
-128.01
Or,m=25,473.99 g
Or,m=25.47 Kg
For the first case m is 25.47 Kg..
For the second case we are given,
m₁= The recorded value of mass
= 0.13 Kg
P= Precision of the mass
=0.005 Kg
So, according to the formula, m will be,
m=
-0.13
Or,m= 25.87 kg
For the second case m is 25.87 Kg.
For the two cases m has different values, 25.47 Kg≠25.87 Kg.
Therefore we can conclude that, these two objects have different masses.
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