6. A car moving in a straight line at constant speed:
1 answer:
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Answer:
v₂ = 176.24 m/s
Explanation:
given,
angle of projectile = 45°
speed = v₁ = 150 m/s
for second trail
speed = v₂ = ?
angle of projectile = 37°
maximum height attained formula,
now,
now, equating both the equations
v₂² = 31061.79
v₂ = 176.24 m/s
velocity of projectile would be equal to v₂ = 176.24 m/s
Explanation:
Value of the cross-sectional area is as follows.
A =
= 3.45
The given data is as follows.
Allowable stress = 14,500 psi
Shear stress = 7100 psi
Now, we will calculate maximum load from allowable stress as follows.
=
= 50025 lb
Now, maximum load from shear stress is as follows.
=
= 48990 lb
Hence, will be calculated as follows.
= 48990 lb
Thus, we can conclude that the maximum permissible load is 48990 lb.