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4 years ago

Write an inequality to model the situation. the maximum speed on the highway , x is 55 mi/h

Mathematics

2 answers:

Mekhanik [1.2K]4 years ago

8 0

Answer:

We have been given the maximum speed on the highway which is 55 mi/hr

So, it has to be less than or equal to 55 because maximum it can go up to 55.

The required inequality will be $x\leq55$

We can take an example of a moving car on a highway which is moving with the speed of 45 mi/hr

And also the stationary car on highway because its speed will be zero which is satisfying the inequality condition.

OLEGan [10]4 years ago

6 0

A maxm speed of 55 mph means that the speed has to be lexx than or equal to 55

x <= 55

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If you place 35 points on a piece of paper so that no three points are in a line, how many line segments are necessary to connec

Ganezh [65]

Thank you for posting your Math question here at brainly. The line segments that are necessary to be connected to each point is 34. The total number of such connection is C(35,2) = 35 * 34/2. I hope the answer helps.

4 0

3 years ago

Read 2 more answers

The grocery store sells 4 pints of strawberries for 13.80 how much does it cost per pint

Mashcka [7]

Answer:

3.45

Step-by-step explanation:

if 4 pints are 13.80 you would have to divided 13.80 by 4 and 4 by 4 to get 1 over blank. The denominator would be 3.45 which would be the amount 1 pint cost. If you don't want to do it as fractions you can simply divide 13.80 by 4.

5 0

3 years ago

Read 2 more answers

X+78=3x-2 ..................

photoshop1234 [79]

Answer:

$x=40$

Step-by-step explanation:

$x+78=3x-2\\\mathrm{Subtract\:}78\mathrm{\:from\:both\:sides}\\x+78-78=3x-2-78\\x=3x-80\\\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}\\x-3x=3x-80-3x\\\\$

$-2x=-80\\\frac{-2x}{-2}=\frac{-80}{-2}\\x=40$

6 0

4 years ago

I'm done with this test, just exhausted from it. Brainly do your magic.

olya-2409 [2.1K]

Answer:

4.5

Step-by-step explanation:

when the height is 0 the ball will hit the ground

so the equation is

-12t²+54t=0

12t²-54t=0

2t²-9t=0

t(2t-9)=0

t=0

t=4.5

so the answer is

4.5

4 0

3 years ago

We are going to fence in a rectangular field that encloses 75 ft2. Determine the dimensions of the field that will require the l

pychu [463]

Answer:

For width W and length L, we have:

W = L = √(75ft^2) = 8.66ft

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = L*W

and the perimeter is:

P = 2*L + 2*W

First, we know that the area of our rectangle is:

A = 75ft^2 = L*W

And we want to minimize the perimeter of our rectangle, then we need to minimize:

P = 2*L + 2*W

From the equation:

75ft^2 = L*W

We can isolate one of the variables, let's isolate L

L = (75ft^2)/W

We could replace this in the perimeter equation:

P(W) = 2*( (75ft^2)/W) + 2*W

P(W) = (150 ft^2)/W + 2*W

To find the minimum of the perimeter we need to look at the zero of the first derivative of P(W).

P'(W) = dP(W)/dW = -(150ft^2)/W^2 + 2

Now we need to find the value of W such that:

P'(W) = 0

0 = -(150ft^2)/W^2 + 2

(150 ft^2)/W^2 = 2

(150ft^2) = 2*W^2

(150ft^2)/2 = W^2

75 ft^2 = W^2

√(75ft^2) = W = 8.66ft

And remember that:

L = (75ft^2)/W

replacing with W = √(75ft^2)

L = (75ft^2)/√(75ft^2) = √(75ft^2)

Then:

W = L = √(75ft^2) = 8.66ft

6 0

3 years ago