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Y_Kistochka [10]
3 years ago
14

Need a little help with these 2 questions :) *if you don’t know, don’t put anything*

Chemistry
1 answer:
Svetlanka [38]3 years ago
8 0

Answer:

first question: 16.5 sleps

second question: 1.50 moles

Explanation:

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for: rate=k[A]^x determine the value of x if the rate doubles when [A] is doubled; and if the rate quadruples when [A] is double
Rom4ik [11]
<span>1. The value of x if the rate doubles when [A] is doubled is that </span><span>x = 1 

</span><span>2. Then if the rate quadruples when [A] is doubled is that x= 2
Since x=1 when the rate doubles, so if it quadruples, it will be times 2.
So the solution to this is 1 times 2= 2
x=2</span>
5 0
4 years ago
Read 2 more answers
PLEASE HELP QUICK// WILL AWARD BRANLIEST
Tom [10]

The correct answer is option C, that is, far greater than 118 as elements combine in different ways.  

The estimated number of compounds produced by the elements in the periodic table is much greater than 118 as elements can combine in different manners. Compounds are the substances comprising more than one element that is held together with chemical bonds. In addition, they can be transformed into a distinct chemical composition by associating with another compound through a chemical reaction.  


7 0
3 years ago
Read 2 more answers
In the first recrystallization, after the solid has been dissolved in warm acetone, the solution is allowed to cool slowly to ro
zvonat [6]

Answer:

See explanation below.

Explanation:

In the older procedure, the solution is cooled so quickly that the recrystallization can be less effective. By allowing the solution to cool slowly, the maximum amount of crystal is formed, and also the impurities are trapped, so the process is more controlled than by the older one.

6 0
3 years ago
Given the initial rate data for the reaction being A + B + C --&gt; D determine the rate expression for the reaction and the (k)
Vesnalui [34]

Answer:

k = 100 mol⁻² L² s⁻¹, r= k[A][B]²

Explanation:

A + B + C --> D

[A] [B] [C] IRR

0.20 0.10 0.40 .20

0.40 0.20 0.20 1.60

0.20 0.10 0.20 .20

0.20 0.20 0.20 .80

Comparing the third and fourth reaction, the concentrations of A and C are constant. Doubling the concentration of B causes a change in the rate of the reaction by a factor of 4.

This means the rate of reaction is second order with respect to B.

Comparing reactions 2 and 3, the concentrations of B and C are constant. Halving the concentration of A causes a change in the rate of the reaction by a factor of 2.

This means the rate of reaction is first order with respect to A.

Comparing reactions 1 and 3, the concentrations of A and B are constant. Halving the concentration of A causes no change in the rate of the reaction.

This means the rate of reaction is zero order with respect to C.

The rate expression for this reaction is given as;

r = k [A]¹[B]²[C]⁰

r= k[A][B]²

In order to obtain the value of the rate constant, let's work with the first reaction.

r = 0.20

[A] = 0.20 [B] = 0.10

k = r / [A][B]²

k = 0.20 / (0.20)(0.10)²

k = 100 mol⁻² L² s⁻¹

8 0
4 years ago
What happens if you pour water in baking soda? Does it release energy? What kind?
alexandr1967 [171]

Answer:

When baking soda or sodium Bicarbonate (NaHCo3) reacts with water carbonic acid is formed . The reaction is exothermic (so yes releases energy) that is heat (type of energy released) and Carbonic acid are produced. Carbonic acid is unstable so breaks up into carbon dioxide (which is the fizzy gas you see) and water forms.

Explanation:

5 0
4 years ago
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