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MakcuM [25]
3 years ago
8

Write a balanced chemical equation for the standard formation reaction of gaseous hydrogen iodide

Chemistry
1 answer:
shusha [124]3 years ago
5 0

Answer:

The balanced chemical equation for standard formation reaction of gaseous hydrogen iodide is

H2 + I2 gives 2HI.

enthalpy change of gaseous hydrogen iodide is 26.5 kJ/ mol

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The equilibrium constant for the reaction
Hitman42 [59]

The question is incomplete, here is the complete question:

The equilibrium constant for the reaction

N₂O₄(g)⇌2NO₂ at 2°C is Kc = 2.0

If each yellow sphere represents 1 mol of N₂O₄(g) and each gray sphere 1 mol of NO₂ which of the following 1.0 L containers represents the equilibrium mixture at 2°C?

The image is attached below.

<u>Answer:</u> The system which represents the equilibrium having value of K_c=2.0 is system (b)

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c

For a general chemical reaction:

aA+bB\rightarrow cC+dD

The expression for K_{c} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

For the given chemical equation:

N_2O_4(g)\rightleftharpoons 2NO_2

The expression of K_c for above equation follows:

K_c=\frac{[NO_2]^2}{[N_2O_4]}      .......(1)

We are given:

Volume of the container = 1.0 L

Value of K_c = 2.0

Molarity of the substance is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume}}

For the given images:

  • <u>For a:</u>

Number of Gray spheres = 8 moles

Number of yellow spheres = 4 moles

Putting values in expression 1, we get:

K_c=\frac{(8/1)^2}{(4/1)}\\\\K_c=16

  • <u>For b:</u>

Number of Gray spheres = 4 moles

Number of yellow spheres = 8 moles

Putting values in expression 1, we get:

K_c=\frac{(4/1)^2}{(8/1)}\\\\K_c=2

  • <u>For c:</u>

Number of Gray spheres = 6 moles

Number of yellow spheres = 6 moles

Putting values in expression 1, we get:

K_c=\frac{(6/1)^2}{(6/1)}\\\\K_c=6

  • <u>For d:</u>

Number of Gray spheres = 2 moles

Number of yellow spheres = 8 moles

Putting values in expression 1, we get:

K_c=\frac{(2/1)^2}{(8/1)}\\\\K_c=\frac{1}{2}

Hence, the system which represents the equilibrium having value of K_c=2.0 is system (b)

3 0
3 years ago
Which of the following ions is formed when a base is dissolved in a solution?
Aneli [31]

Answer:

\huge\boxed{\sf OH-}

Explanation:

<u>According to Arrhenius concept of acid and base:</u>

"When a base in a solution, produces/yields OH- (Hydroxide) ions."

So, when a base is dissolved in a solution, it produces OH- ions.

<u>For example:</u>

NaOH ⇄ Na⁺ + OH⁻ (So, it is a base)

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
3 0
2 years ago
Which statement is true about this reaction? mc016-1.jpg
Julli [10]
C because,  its products is heavier than each of its reactants
8 0
4 years ago
How do you make liquid nitrogen icecream
Harrizon [31]
<span>Add any other </span>liquid<span> flavorings you might want. Put on your gloves and goggles. Pour a small amount of </span>liquid nitrogen<span> directly into the bowl with the </span>ice cream<span> ingredients. Continue to stir the </span>ice cream<span>, while slowly adding more </span>liquid nitrogen<span>.</span>
7 0
3 years ago
Read 2 more answers
What does Hess's law state about the total enthalpy change for a reaction?OA. It depends on the reaction pathway.B. It can only
Dimas [21]
<h2>Answer:</h2>

Option D is correct. It is independent of the reaction pathway.

<h2>Explanations:</h2><h2>What is Hess's law?</h2>

Hesslaw states that the enthalpy change of a reaction does not change regardless whether the reaction takes place in a single or multiple reaction pathways.

This shows that the total entalpy change of a reaction does not depend on the reaction pathway.

8 0
1 year ago
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