1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
konstantin123 [22]
3 years ago
14

What is the volume of a sample of liquid mercury that has a mass of 76.2g, given that the density of mercury is 13.6g/mL?

Chemistry
1 answer:
nignag [31]3 years ago
8 0
Hey there!

D  = m / V

13.6 = 76.2 / V

V = 76.2 / 13.6

V = 5.602 mL
You might be interested in
What is most likely true about ocean temperatures surrounding Australia, which is marked by the star in the following map?
aivan3 [116]
The answer that is most likely true about ocean temperatures surrounding Australia, which is marked by the star in the following map is that b) the ocean temperatures north of Australia are higher than the ocean temperatures south of Australia. 
6 0
4 years ago
Read 2 more answers
What type of change is this picture showing?
sladkih [1.3K]

Answer: physical

Explanation: freezing and melting are physical changes.

8 0
3 years ago
वर्षा का हमारे जीवन में क्या महत्व<br><br>है?​
Snezhnost [94]

Answer:

Rain is liquid water in the form of droplets that have condensed from atmospheric water vapor and then become heavy enough to fall under gravity. Rain is a major component of the water cycle and is responsible for depositing most of the fresh water on the Earth. It provides suitable conditions for many types of ecosystems, as well as water for hydroelectric power plants and crop irrigation.

7 0
3 years ago
How many moles of NaCl are equivalent to 15.6<br> grams of NaCl
NeX [460]

One mole of NaCl has a mass of approximately 58.5 grams. This gives it a conversion factor of 1/58.5

Hope This Helped

4 0
4 years ago
Determine the empirical formula of a compound containing 48.38 grams of carbon, 8.12 grams of hydrogen, and 53.5 grams of oxygen
Dafna1 [17]

As with most stoichiometry problems, it is necessary to work in moles. The ratio of the moles of each element will provide the ratio of the atoms of each element.

Get the mass of each element by assuming a certain overall mass for the sample (100 g is a good mass to assume when working with percentages).

Remeber that percentages are a ratio multiplied by 100. You must convert percentages back to their decimal value before working with them.

(.4838) (100 g) = 48.38 g C

(.0812 ) (100 g) = 8.12 g H

(.5350) (100 g) = 53.38 g O

Convert the mass of each element to moles of each element using the atomic masses.

(48.38 g C) (1 mol/ 12.10 g C) = 4.028 mol C

(8.12 g H) (1 mol/ 1.008 g H) = 8.056 mol H

(53.38 g O) (1 mol/ 16.00 g O) = 3.336 mol O

Find the ratio or the moles of each element by dividing the number of moles of each by the smallest number of moles.

Use the mole ratio to write the empirical formula.

6 0
3 years ago
Other questions:
  • What would the expected temperature change be (in Fahrenheit) ida 0.5 gran sample of water released 50.1 J of heat energy? The s
    11·1 answer
  • A. True <br> b. False a chemical species is either an acid or a base, it cannot function as both
    9·1 answer
  • Describe how to separate a mixture of sugar and water.
    6·2 answers
  • What energy is required to move from Ca+Ca+ to Ca2+Ca2+ + e−e−?
    6·1 answer
  • an isotope of cesium (cesium-137) has a half-life of 30 years if 1.0g of cesium-137 disintegrates over a period of 90 years how
    5·1 answer
  • How does an earthquake affect the geosphere
    10·1 answer
  • Which symbol can be used to indicate the pressure at which a chemical reaction is carried out? 25 degrees Celsius over a right a
    11·2 answers
  • Answers fast please Gets oxygen into your body and carbon dioxide out
    5·2 answers
  • Population from the phylogenetic tree?
    13·1 answer
  • 5.Write the seasons in order starting with fall:
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!