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MatroZZZ [7]
3 years ago
13

A student has 100. mL of 0.400 M M CuSO4(aq) and is asked to make 100. mL of 0.150 M CuSO4(aq) for a spectrophotometry experimen

t. The following laboratory equipment is available for preparing the solution: centigram balance, weighing paper, funnel, 10 mL beaker, 150 mL beaker, 50 mL graduated cylinder, 100 mL volumetric flask, 50 mL buret, and distilled water.
Calculate the volume of 0.400 M CuSO4(aq) required for the preparation
Chemistry
1 answer:
cupoosta [38]3 years ago
6 0

Answer:

37.5 mL

Explanation:

To solve this problem we can use the formula:

  • C₁V₁ = C₂V₂

C₁ = 0.400 M

V₁ = ?

C₂ = 0.150 M

V₂ = 100 mL

So now we <em>solve for V₁</em>:

  • 0.400 M * V₁ = 0.150 M * 100 mL
  • V₁ = 37.5 mL

So we need 37.5 mL of 0.400 M CuSO₄(aq) to make 100 mL of 0.150 M CuSO₄(aq). That volume could be measured in the 50 mL buret.

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If atoms really conformed to the plum pudding model of the atom, what would the results of rutherford’s experiment have been?
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Rutherford's experiment was done to prove Thompson's Plum Pudding Model. In this model, the protons and electrons are both inside the nucleus. The atoms is neutral because the charges cancel out. Rutherford's hypothesis was that, when a beam of cathode rays hits the gold foil, all the light should pass through. If the Plum Pudding model was correct, that would have been the result. However, it wasn't. 
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3 years ago
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(b) difference between metalloids and alloys​
blsea [12.9K]

Answer:

<u>Metalloid -</u>

A metalloid is a chemical element with properties intermediate between those of typical metals and nonmetals

<u>Alloy</u> -

An alloy is a mixture of metals or a mixture of a metal and another element. Alloys are defined by a metallic bonding character.

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3 years ago
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If 200.0 g of copper(II) sulfate react with an excess of zinc metal, what is the theoretical yield of copper? 1.253 g 50.72 g 79
Helen [10]
1)we need a balanced equation: CuSO₄ + Zn ---> ZnSO₄ + Cu

2) we need to convert the grams of CuSO₄ to moles using the molar mass. 

molar mass CuSO₄= 63.5 + 32.0 + (4 x 16.0)= 160 g/mol

200.0 g CuSO_4 ( \frac{1 mol}{160 grams} )= 1.25 mol CuSO_4

3) convert moles of CuSO₄ to moles of Cu

1.25 mol CuSO_4 ( \frac{1 mol Cu}{1 mol CuSO_4} )= 1.25 mol Cu

4) convert moles of Cu to grams using it's molar mass.

molar mass Cu= 63.5 g/mol

1.25 mol (\frac{63.5 grams}{1 mol} )= 79.4 grams Cu

I did it step-by-step as the explanation but you can do all of this in one step. 

200.0 g CuSO_4 ( \frac{1 mol CuSO_4}{160 g} ) ( \frac{1 mol Cu}{1 mol CuSO_4} ) ( \frac{63.5 grams}{1 mol Cu} )= 79.4 grams Cu


4 0
4 years ago
A 3.96x10^-24 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000-cm cuvet; a blank solution containi
viktelen [127]

Actual question from source:-

A 3.96x10-4 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000 cm cuvette.  A blank had an absorbance of 0.029.  The absorbance of an unknown solution of compound A was 0.375.  Find the concentration of A in the unknown.

Answer:

Molar absorptivity of compound A = 1502.53\ {Ms}^{-1}

Explanation:

According to the Lambert's Beer law:-

A=\epsilon l c

Where, A is the absorbance

 l is the path length  

\epsilon is the molar absorptivity

c is the concentration.  

Given that:-

c = 3.96\times 10^{-4}\ M

Path length = 1.000 cm

Absorbance observed = 0.624

Absorbance blank = 0.029

A = 0.624 - 0.029 = 0.595

So, applying the values in the Lambert Beer's law as shown below:-

0.595=\epsilon\times 1.000\ cm\times 3.96\times 10^{-4}\ M

\epsilon=\frac{0.595}{3.96\times 10^{-4}}\ {Ms}^{-1}=1502.53\ {Ms}^{-1}

<u>Molar absorptivity of compound A = 1502.53\ {Ms}^{-1}</u>

4 0
4 years ago
Which salt is formed by the reaction between hydrochloric acid and sodium hydroxide, write with chemical equation. .​
stepan [7]

Answer:

salt sodium chloride (NaCl)

8 0
3 years ago
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