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andrezito [222]

3 years ago

13

You want to know the temperature today. your friend tells you that it is 6 degrees colder than it was on monday. on monday it wa

s -5°
f. what is the temperature today?

2 answers:

Tom [10]3 years ago

8 0

Answer:

-11 degrees

Step-by-step explanation:

Fed [463]3 years ago

3 0

-11 degrees outside today

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Triangle A′B′C′ is the image of triangle ABC after a dilation.

IceJOKER [234]

Answer:

3

Step-by-step explanation:

could the length of the first triangle to the length of the second triangle

7 0

2 years ago

Please help !!!!!!!!!!

Vesna [10]

Answer:

(2, 2) states x=2 and y=2

Considering the inequality:

$y\leq 4x-6$

Is y less than or equal to 2 when x = 2?

$2\leq 4(2)-6\\2\leq 8-6\\2\leq 2\\$

Yes, (2, 2) is a solution for the inequality.

4 0

3 years ago

The last line of a proof represents

WARRIOR [948]

The last line of a proof represents: The conclusion!

5 0

3 years ago

5. Which of the following is the equation of a line. that passes through the points (0.8) and (6.4)7 Use of

andriy [413]

See in the explanation

<h2>Explanation:</h2>

In this exercise, <em>we have the following points:</em>

$(0.8) \\ \\ (6.4)$

And <em>the following linear equations:</em>

$(1) \ y=-x+8 \\ \\ (2) \ y=\frac{3}{2}x+6 \\ \\ (3) \ y=-\frac{4}{5}x+4 \\ \\ (4) \ y=\frac{1}{2}x+8$

When plotting these graphs, we find the following facts:

<h3>For (1):</h3>

We see the graph in the first figure below. The graph only passes through the point (0, 8)

<h3>For (2):</h3>

This is the second graph below. The graph passes neither through point (0, 8) nor (6, 4)

<h3>For (3):</h3>

This is the third graph below. The graph passes neither through point (0, 8) nor (6, 4)

<h3>For (4):</h3>

This is the fourth graph below. The graph only passes through the point (0, 8)

So, <em>there is no any equation of the line that passes through the points (0.8) and (6.4) at the same time.</em>

<em />

<h2>Learn more:</h2>

About lines: brainly.com/question/12169569

#LearnWithBrainly

8 0

3 years ago

For 0 ≤ θ < 2 π what are the solutions to sin^2(θ) =2sin^2(θ/2)

gregori [183]

Recall the half-angle identity for sine,

sin²(x/2) = (1 - cos(x))/2

Then the given equation is identical to

sin²(θ) = 1 - cos(θ)

Also recall the Pythagorean identity,

sin²(θ) + cos²(θ) = 1

Then we rewrite the equation as

1 - cos²(θ) = 1 - cos(θ)

Factoring the left side, we have

(1 - cos(θ)) (1 + cos(θ)) = 1 - cos(θ)

and so

(1 - cos(θ)) (1 + cos(θ)) - (1 - cos(θ)) = 0

and we factor this further as

(1 - cos(θ)) (1 + cos(θ) - 1) = 0

which gives

cos(θ) (1 - cos(θ)) = 0

Then either

cos(θ) = 0 or 1 - cos(θ) = 0

cos(θ) = 0 or cos(θ) = 1

[θ = arccos(0) + 2nπ or θ = -arccos(0) + 2nπ]

… or [θ = arccos(1) + 2nπ or θ = -arccos(1) + 2nπ]

(where n is any integer)

[θ = π/2 + 2nπ or θ = -π/2 + 2nπ] or [θ = 0 + 2nπ]

In the interval 0 ≤ θ < 2π, we get three solutions:

• first solution set with n = 0 ⇒ θ = π/2

• second solution set with n = 1 ⇒ θ = 3π/2

• third solution set with n = 0 ⇒ θ = 0

So, the first choice is correct.

6 0

3 years ago