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-BARSIC- [3]
3 years ago
8

What is the solution to the system of equations ? X=y-3 X+3y=13 . Please solve

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

X=y-3 X+3y=13 so,

first you need to plug in the value of X to make it y-3+3y=13 then you add 3 to both sides and it becomes y+3y=16

After this you can combine the y and 3y to make 4y=16 and you divide both sides by 4 to get y=4

Then you plug 4 in for every time there is a y so, X+3(4)=13 which makes the equation X+12=13 and you subtract 12 from both sides making it X=1

So solution to the system is y=4 and X=1

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Answer:

x=3/8, y=-7/8. (3/8, -7/8).

Step-by-step explanation:

y=-5x+1

y=3x-2

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-5x+1=3x-2

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3 years ago
In APQR, find the measure of Z.P.
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multiple possibilities.

e.g.

we could use Pythagoras to get QR, and then use the law of sine to get angle P.

or we can use the law of sine to get angle R, and then use the rule that the sum of all angles in a triangle is always 180° to get angle P.

I propose the second option :

the law of sine :

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33.8/sin(R) = 57.6/sin(90) = 57.6

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Answer:

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Step-by-step explanation:

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\dfrac{8}{x-3}=\dfrac{14}{x+6}\\\\8(x+6)=14(x-3)\\\\8x+48=14x-42\\\\48+42=14x-8x\\\\90=6x\\\\x=90:6=15

6 0
3 years ago
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