True is the correct answer hope this helps
Answer:
1.85 m/s
102.438 m
Explanation:
From vector motion
The resultant velocity

The magnitude of speed of the speed of the boat relative to a stationary shore observer is 1.85 m/s
The distance covered is 229 m
Time = Distance / Speed

Distance = Speed of current × Time
Distance = 0.756×135.5 = 102.438 m
The boat will be 102.438 m from the initial position is the boat when it reaches the opposite shore
Answer:
20.2 seconds
Explanation:
The airplane (and therefore the crate) initially has no vertical velocity, so v₀ = 0 m/s.
The crate is in free fall, so a = -9.8 m/s².
The crate falls downward, so Δx = -2000 m.
Find: t, the time it takes for the crate to land.
Δx = v₀ t + ½ at²
-2000 m = (0 m/s) t + ½ (-9.8 m/s²) t²
t = 20.2 s
It takes 20.2 seconds for the crate to land.
The correct answer is <span>A. By multiplying the change in mass by the square of the speed of light since the formula is expressed by </span>E = mc².