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3 years ago

Why is the inner core a dense ball of solid metal?

Physics

1 answer:

Zielflug [23.3K]3 years ago

4 0

Answer:

so dont mind this it just said the answer have to be 20 words long (the answer should be B)

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If a 0.75 efficient motor produces 150 W of useful power, what was the input power? *

vlada-n [284]

Answer:

<em>The input power is 200 W</em>

Explanation:

<u>Motor Efficiency</u>

The efficiency of a motor can be calculated as follows:

$\displaystyle \beta=\frac{P_o}{P_i}$

Where:

β = efficiency

Po = Output power

Pi = Input power

Solving for Pi:

$\displaystyle P_i=\frac{P_o}{\beta}$

The efficiency is β=0.75 and the output power is Po=150 W, thus the input power is:

$\displaystyle P_i=\frac{150}{0.75}$

$P_i=200 \ W$

The input power is 200 W

4 0

3 years ago

Metalloids have properties of both ________ and _____________

raketka [301]

Answer:Metaloids have properties of both metals and non-metals.

Explanation:

6 0

3 years ago

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The primary reason a light bulb emits light is due to

Semmy [17]

Answer:

Resistance

Explanation:

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3 years ago

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What is the measure of a change in an object’s velocity?

tiny-mole [99]

It's a measure of the acceleration

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3 years ago

A car traveling at 27 m/s runs out of gas while traveling up a 8.0 ∘ slope. How far will it coast before starting to roll back d

Ad libitum [116K]

Answer:

Approximately $2.7 \times 10^{2}\; \rm m$ along the slope, assuming that no energy was lost to friction.

Explanation:

Let $v$ denote the initial velocity of this vehicle. Let $m$ denote the mass of this vehicle. The kinetic energy (KE) of this vehicle would have initially been:

$\displaystyle \frac{1}{2}\, m \cdot v^{2}$ .

The gain in the gravitational potential energy (GPE) of this vehicle is proportional to the increase in its height.

Let $g$ denote the gravitational field strength. $g \approx 9.81\; \rm m \cdot s^{2}$ on the earth. If the increase in the height of this vehicle is $h$ , this vehicle would have gained GPE:

$m \cdot g \cdot h$ .

Hence, the height of this vehicle is maximal when the GPE of this vehicle is maximized.

Since the vehicle went out of fuel, all its GPE would have been converted from KE. Assuming that no energy was converted to friction. The GPE of this vehicle would be maximal when the entirety of the KE was converted to GPE.

Hence, the maximal GPE of this vehicle would be equal to its initial KE:

$\displaystyle m \cdot g \cdot h = \frac{1}{2}\, m \cdot v^{2}$ .

The maximum height of this vehicle would be:

$\begin{aligned} h &= \frac{(1/2) \, m \cdot v^{2}}{m \cdot g}\\ &= \frac{v^{2}}{2\, g}\end{aligned}$ .

Given that $v = 27\; \rm m\cdot s^{-1}$ , the maximum height of this vehicle would be:

$\begin{aligned} & \frac{v^{2}}{2\, g} \\ =\; & \frac{(27\; \rm m\cdot s^{-1})^{2}}{2 \times 9.81\; \rm m\cdot s^{-2}} \\ \approx \; &37.2\; \rm m\cdot s^{-1}\end{aligned}$ .

Refer to the diagram attached. The distance that this vehicle traveled along the slope would be approximately:

$\begin{aligned}\frac{37.2\; \rm m}{\sin(8.0^{\circ})} \approx 2.7 \times 10^{2}\; \rm m\end{aligned}$ .

6 0

3 years ago