Answer:
he average speed for the airplane is 558 km/hr
Explanati
Answer:
(a) ε = 1373.8.
(b) The wingtip which is at higher potential.
Explanation:
(a) Finding the potential difference between the airplane wingtips.
Given the parameters
wingspan of the plane is = 18.0m
speed of the plane in north direction is = 70.0m/s
magnetic field of the earth is = 1.20μT
The potential difference is given as:
ε = Blv
where ε = potential difference of wingtips
B = magnetic field of earth
l = wingspan of airplane
v = speed of airplane
ε = 1.2 x 18.0 x 63.6
ε = 1373.8
(b) Which wingtip is at higher potential?
The wingtip which is at higher potential.
<h2>
<u>Required</u><u> </u><u>Answer</u><u>:</u></h2>
The body will <u>stay at rest </u>(Option D). It is because a force of magnitude 50 N is pulled towards left and another force is pulling it towards right with same magnitude 50 N. So, the direction of force is opposite and magnitude is same i.e. 50 N. So, they will cancel each other and net force is 0. Hence, there would be no acceleration.
- Option A - Showing acceleration
- Option B - Showing acceleration
- Option C - Change of direction due to Net force
Hence, these options are incorrect because they are only possible when net external force is non-zero. Staying at rest i.e. Option D means there is no motion and hence no acceleration, this shows that net force is 0![.](https://tex.z-dn.net/?f=.)
<u>━━━━━━━━━━━━━━━━━━━━</u>
False its atmosphere, lithosphere, hydrosphere, and boisphere
If friction is acting along the plane upwards
then in this case we will have
For equilibrium of 100 kg box on inclined plane we have
![mgsin\theta = F_f + T](https://tex.z-dn.net/?f=mgsin%5Ctheta%20%3D%20F_f%20%2B%20T)
also for other side of hanging mass we have
![T = Mg = 50(9.8) = 490 N](https://tex.z-dn.net/?f=T%20%3D%20Mg%20%3D%2050%289.8%29%20%3D%20490%20N)
now we have
![100(9.8)sin\theta = 100 + 490](https://tex.z-dn.net/?f=100%289.8%29sin%5Ctheta%20%3D%20100%20%2B%20490)
![980sin\theta = 590](https://tex.z-dn.net/?f=980sin%5Ctheta%20%3D%20590)
![sin\theta = 0.602](https://tex.z-dn.net/?f=sin%5Ctheta%20%3D%200.602)
![\theta = 37 degree](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2037%20degree)
In other case we can assume that friction will act along the plane downwards
so now in that case we will have
![mgsin\theta + F_f = T](https://tex.z-dn.net/?f=mgsin%5Ctheta%20%2B%20F_f%20%3D%20T)
also we have
![T = Mg = 50(9.8) N](https://tex.z-dn.net/?f=T%20%3D%20Mg%20%3D%2050%289.8%29%20N)
now we have
![100(9.8)sin\theta + 100 = 50(9.8)](https://tex.z-dn.net/?f=100%289.8%29sin%5Ctheta%20%2B%20100%20%3D%2050%289.8%29)
![980sin\theta + 100 = 490](https://tex.z-dn.net/?f=980sin%5Ctheta%20%2B%20100%20%3D%20490)
![980 sin\theta = 490 - 100](https://tex.z-dn.net/?f=980%20sin%5Ctheta%20%3D%20490%20-%20100)
![sin\theta = 0.397](https://tex.z-dn.net/?f=sin%5Ctheta%20%3D%200.397)
![\theta = 23.45 degree](https://tex.z-dn.net/?f=%5Ctheta%20%3D%2023.45%20degree)
<em>So the range of angle will be 23.45 degree to 37 degree</em>