Answer:
Final temperature attained by water = 34.6°C
Explanation:
The reaction of CaO and H₂O is an <em>exothermic reaction</em>. The equation of reaction is given below:
CaO + H₂O ----> Ca(OH)₂
The quantity of heat given off, ΔH°rxn = 64.8KJ/mol = 64800J/mol
Number of moles of CaO = mass/molar mass, where molar mass of Ca0 = 56g/mol, mass of CaO = 10.1g
Number of moles of CaO = 10.1g/56g/mol =0.179moles
Quantity of heat given off by 0.179 moles = 64800 *0.179 = 11599.2J/mol
Using the formula, <em>Quantity of heat, q = mass * specific heat capacity * temperature rise.</em>
mass of mixture = (10.1 + 157)g = 167.1g, Initial temperature = 18.0°C
Final temperature(T₂) - Initial temperature(T₁) = Temperature rise
11599.2J/mol = 167.1g * 4.18J/g·°C * ( T₂ - 18.0°C)
11599.2 = 698.478T₂ - 12572.604
11599.2 + 12572.604 = 698.478T₂
698.478T₂ = 24171.804
T₂ = 34.6°C
Therefore, final temperature attained by water = 34.6°C
Answer:
A reaction is non-spontaneous at any temperature when the Gibbs free energy > 0.
Explanation:
There is a state function, that determines if a reaction is sponaneous or non spontaneous:
ΔG = Gibbs free energy
A reaction is non spontaneous when it does require energy to produce that reaction. It will be spontaneous, when the reaction does not require energy to be occured.
The formula is: ΔG = ΔH - T.ΔS
ΔH → Enthalpy → Energy gained or realeased as heat.
ΔH < 0 → <em>Exothermic reaction. Spontaneity is favored
</em>
T → Temperature
ΔS → Entropy → Degree of disorder of a system.
When the system has a considered disorder ΔS > 0, disorder increases.
When the system is more ordered, ΔS < 0, disorder decreases.
The reaction will be non spontaneous if, the enthalpy is positive (endothermic reaction) and the ΔS < 0 (disorder decreases). It will not occur if we do not give energy.
ΔG < 0 → Spontaneous reaction
ΔG > 0 → Non spontaneous reaction
ΔG = 0 → System in equilibrium
Answer:
19.29 g.cm⁻³
Solution:
Data Given:
Mass = 301 g
Volume = 15.6 cm³
Formula Used:
Density = Mass ÷ Volume
Putting values,
Density = 301 g ÷ 15.6 cm³
Density = 19.29 g.cm⁻³
We have that the name (not chemical symbol) of the main group element in period 5 and group 3A is
Metalloid boron (B)
From the Question we are told that
The element belongs to
Period 5 and group 3A
Generally
Group 3A of the periodic table includes the metalloid boron (B), aluminum (Al), indium (In), and thallium (Tl) gallium (Ga),
Period 5 is possessed by the metalloid boron (B) of the Group 3A
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