Answer:
<h3>The answer is 25 mL</h3>
Explanation:
The new volume can be found by using the formula for Boyle's law which is
![P_1V_1 = P_2V_2](https://tex.z-dn.net/?f=P_1V_1%20%3D%20P_2V_2)
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we are finding the new volume
![V_2 = \frac{P_1V_1}{P_2} \\](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7BP_1V_1%7D%7BP_2%7D%20%20%5C%5C)
From the question we have
![V_2 = \frac{75 \times 1.5}{4.5} = \frac{112.5}{4.5} \\](https://tex.z-dn.net/?f=V_2%20%3D%20%20%5Cfrac%7B75%20%5Ctimes%201.5%7D%7B4.5%7D%20%20%3D%20%20%5Cfrac%7B112.5%7D%7B4.5%7D%20%20%5C%5C%20)
We have the final answer as
<h3>25 mL</h3>
Hope this helps you
Answer:
0.174 M
Explanation:
The same can be solve by using Nernst's equation
The Nernst's equation is:
![Ecell=E^{0}_{cell}-\frac{0.0592}{n}log\frac{[anodic]}{[cathodic]}](https://tex.z-dn.net/?f=Ecell%3DE%5E%7B0%7D_%7Bcell%7D-%5Cfrac%7B0.0592%7D%7Bn%7Dlog%5Cfrac%7B%5Banodic%5D%7D%7B%5Bcathodic%5D%7D)
For silver cell
n= 1
As both the compartments have silver nitrate solution,t the standard emf of cell will be zero.
Given
Ecell = 0.045
[Anodic compartment]= 1 M
Putting values
![0.045 = 0 -\frac{0.0592}{1}log(\frac{1}{x} )](https://tex.z-dn.net/?f=0.045%20%3D%200%20-%5Cfrac%7B0.0592%7D%7B1%7Dlog%28%5Cfrac%7B1%7D%7Bx%7D%20%29)
![0.760=log(\frac{1}{x})](https://tex.z-dn.net/?f=0.760%3Dlog%28%5Cfrac%7B1%7D%7Bx%7D%29)
Taking antilog and solving
[AgNO3]=0.174 M
A) 0.875 M of MgBr2 is 0.875 mol/L
B) 23.7 mL = 0.0237 L
0.875 mol => 1 L
x mol => 0.0237 L
Cross multiply
1x = 0.875 × 0.0237
x = 0.0207 mol
>> In 23.7 mL of 0.875 M MgBr2 solution there is 0.0207 moles of MgBr2
C) Molar mass of MgBr2 (*) = 24.305 + (2 × 79.904) = 184.113 g/mol
184.113 g => 1 mol
x g => 0.0207 mol
Cross multiply
1x = 184.113 × 0.0207
x = 3.8111 g
>> 0.0207 moles of MgBr2 is equivalent to 3.81 g of MgBr2
>> In 23.7 mL of 0.875 M MgBr2 solution there is 3.81 g of MgBr2
(*) Use your periodic table
Answer:
After leaving the small intestines, the undigested food enters the colon ( large intestines)
Explanation:
When the chyme is exhausted of its nutrients, the remaining waste material changes into the semi solids called as feces. These pass into the large intestine, where gut flora further break residual proteins and starches.
Water is absorbed here and the remaining waste matter is stored prior to defecation.
The passage of the digesting food in the colon is a lot slower, taking about 12 to 50 hours until it is removed by defecation. The colon mainly serves as a site for the fermentation of digestible matter by the gut flora.
Colon is the largest part of the GI tract.
The correct answer is option C, the periodic table and a chemistry website.
Maria is researching a family of elements so besides her school textbook, Maria should refer to the periodic table and a chemistry website.
In the periodic table a family of elements such as the halogen or inert gases are grouped together based on their atomic number and periodicty of their properties. Maria can observe and learn about their periodic properties such as atomic radii, electronegativity, ionization potential, nature of bonding, and more.
Also a chemistry website that discusses the physical and chemical properties of a family of elements would be relevant.