Answer:
the length of the Nichrome wire is <em>59.88 m</em>
<em></em>
Explanation:
The resistance of a wire is determined by:
P = V² / R or R = V² / P
where
- V is the voltage
- R is the resistance
- P is the power
We also know that
R = PL / A
where
- A is the area and it is equal to πr²
- P = 3.20 × 10² W
Therefore, the length of the Nichrome wire is
L = RA / ρ
L = (V²/P)(πr²) / ρ
L = V²πr² / ρ P
L = (110 V)²(π)(7.1 × 10⁻⁴ m)² / (3.2 × 10² W)(100 × 10⁻⁸ Ω·m)
<em>L = 59.88 m</em>
Here is the link with ans on it
https://moorsscience.wikispaces.com/file/view/chapter+12+answers.pdf
hope it helps
Machines capable of manufacturing exactly the same component time after time,
with exactly the resistance you want, would be very expensive, and so would the
products they turn out. A resistor would cost a dollar instead of a few pennies.
The machine itself, and its output, work within tolerances.
The cheapest mass-produced resistors are guaranteed to be within 20% above
or below the resistance marked on them. And you know what ? For most bench-
work and prototyping, that's usually close enough.
False because opposites attract. :)
F=ma
F=125 N
m= 50 kg
125=50a
a=2.5 m/s^2
