PE = mgh
Mass, m = 7kg, g ≈ 10 m/s², height = 2m
= 7*10*2
= 140 Joules.
Partial Lunar Eclipse:
A partial lunar eclipse is when the earth gets between the Sun and Moon. However, all three bodies are not in alignment meaning we are able to see some more like part of the moon's surface as it moves in route of the Earth's shadow.
Total Lunar Eclipse:
The three celestial bodies are perfectly aligned which allows for the earth to completely block the sun's rays from hitting/reaching the moon. The sun is positions is in back of the Earth which then causes the shadow of the earth to be cast on the Moon covering the moon completely. When that happens you get the phenomenon called a total lunar eclipse.
Hopefully this helped and good luck.
<h3>Question:</h3>
How to find g (acceleration due to gravity)
<h3>Solution:</h3>
We know,
Acceleration due to gravity (g)
![= \frac{GM}{ {R}^{2} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7BGM%7D%7B%20%7BR%7D%5E%7B2%7D%20%7D%20)
where, G = Gravitational constant
![= 6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \\](https://tex.z-dn.net/?f=%20%3D%206.67%20%5Ctimes%20%20%7B10%7D%5E%7B11%7D%20N%20%7Bm%7D%5E%7B2%7D%2Fk%20%7Bg%7D%5E%7B2%7D%20%20%5C%5C%20)
M = Mass of the earth
![= 6 \times {10}^{24} \: kg](https://tex.z-dn.net/?f=%20%3D%206%20%5Ctimes%20%20%7B10%7D%5E%7B24%7D%20%5C%3A%20%20kg)
R = Radius of the earth
![= 6.4 \times {10}^{6} m](https://tex.z-dn.net/?f=%20%3D%206.4%20%5Ctimes%20%20%7B10%7D%5E%7B6%7D%20m)
Putting these values of G, M and R in the above formula, we get
![g \: = \: \frac{6.67 \times {10}^{11} N {m}^{2}/k {g}^{2} \times \: 6 \times {10}^{24} \: kg }{(6.4 \times {10}^{6}m {)}^{2} } \\ = 9.8m/ {s}^{2}](https://tex.z-dn.net/?f=g%20%5C%3A%20%20%3D%20%20%5C%3A%20%20%5Cfrac%7B6.67%20%5Ctimes%20%20%7B10%7D%5E%7B11%7D%20N%20%7Bm%7D%5E%7B2%7D%2Fk%20%7Bg%7D%5E%7B2%7D%20%20%20%5Ctimes%20%5C%3A%206%20%5Ctimes%20%20%7B10%7D%5E%7B24%7D%20%5C%3A%20%20kg%20%7D%7B%286.4%20%5Ctimes%20%20%7B10%7D%5E%7B6%7Dm%20%7B%29%7D%5E%7B2%7D%20%20%7D%20%20%5C%5C%20%20%3D%209.8m%2F%20%7Bs%7D%5E%7B2%7D%20)
So, the value of acceleration due to gravity is
![9.8m/s ^{2}](https://tex.z-dn.net/?f=9.8m%2Fs%20%5E%7B2%7D%20)
Hope it helps.
Do comment if you have any query.
<span>10 times as much. Since F=m*a, and a is constant, the only thing that affects force is the mass.
In response to the below answer, the acceleration due to gravity does not change. The force due to gravity definitely DOES change depending on the mass of the object. Since the force is what the problem asks for, the answer is 10</span>