I think b support body weight
Answer:
firstly,
ke=1÷2mv^2
on putting same ke by increasing mass by 16 times new velocity becomes v'
then
ke=1÷2×16m×v'^2
from above we can write
1÷2mv^2=1÷2×16m×v'^2
v^2=16v'^2
1÷4v=v'
hence original velocity should be decreased by 4 times to keep same ke
3) Earth is about 150 million km from the Sun, and the apparent brightness of the Sun in our sky is about 1,300 watts per square meter. Determine the apparent brightness we would measure for the Sun if we were located five times Earth's distance from the Sun. Answer: The Sun would appear 1/25 times as bright.
very interesting and amazing question u had asked but i get it...
Answer
W = Force × Displacement
- but in above case force is exerted on the men as the weight of the child × gravitational pull of earth (9.8 m/s^2) but the displacement or movement is ZERO
- there for W= F×0 =0
- so even after carrying child for 2 hours work done by the men will be zero
<u>More</u><u> </u><u>examples</u>
- a person standing straight and lifting weight
- a person carry some weight and walk in a circular path and came back to its original position.........in this case also Displacement will be zero
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hope it helped u buddy
Answer: counterclockwise
Explanation:
As the area of the loop decreases steadily, the flux through the loop also decreases. By Lenz’s law, any induced current will tend to oppose the decrease. Using Flemming right hand rule (Fleming's right-hand rule which shows the direction of induced current) we know that magnetic field inside the loop due to a counterclockwise current comes out of the plane. Therefore a counterclockwise current will create a stronger magnetic field inside
the loop, tending to increase the flux.
When a wire loop is moved in the direction of the current or a wire loop is being pulled through a uniform magnetic field there would be no induced current ( current loop is said to be zero)
