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Shkiper50 [21]
3 years ago
15

What is the main function of a telescope?

Physics
2 answers:
OLga [1]3 years ago
6 0
Telescope magnifies light coming from distant objects.
Alla [95]3 years ago
6 0

Answer:

It magnifies light received from distant objects.

Explanation:

Telescope is an arrangement of lenses and mirrors which enable us to see us the objects which are far away from us. This happens as the telescope magnifies the objects. It uses a convex lens or concave mirror to collect the light and magnify it. Convex lens and concave mirror are used to see things magnified.

In telescope, either two convex lenses of different focal length or a concave mirror and a convex lens of different focal length are used for magnifying.

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A water molecule consists of an oxygen atom with two hydrogen atoms bound to it. The angle between the two bonds is 106◦ . If ea
balu736 [363]

Answer:

easy 16

Explanation:

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4 years ago
I need to show my work as well but on the computer so, please show work for how you got the answers. Thank you!
balandron [24]

Answer:

1) 1H_2 + 1Cl_2 => 2HCl

2) 2Al + 6HCl => 2AlCl_3 + 3H_2

3) 1Ca_2Br_2 + 2NaCO_3 => 2CaCO_3 + 2NaBr

4) 3NaOH + 1FeCl_3 => 3NaCl + 1Fe(OH)_3

Explanation:

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3 years ago
A mars prototype carrying scientific instruments has a mass of 1060kg. a net force of 52000 n is applied to this roverat a test
Nitella [24]

F = 52000 N

m = 1060 kg

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8 0
4 years ago
I will mark as the brainliest answer<br><br>plz 8,9,10​
blagie [28]

Answer:

8.  acceleration = \dfrac{d(velocity)}{d(time)}  = 1 unit .

9. acceleration = \dfrac{d(velocity)}{d(time)}  = -1 unit.

10. acceleration = \dfrac{d(velocity)}{d(time)}  = 0 units.

Explanation:

8. i) acceleration = velocity / time

  ii) In this figure velocity = time

  iii) therefore acceleration = \dfrac{d(velocity)}{d(time)} = 1 unit .

9. i) acceleration = velocity / time

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     therefore velocity = (-0.5 \times time) + 5

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5 0
3 years ago
You just calibrated a constant volume gas thermometer. The pressure of the gas inside the thermometer is 294.0 kPa when the ther
Travka [436]

Answer: 361° C

Explanation:

Given

Initial pressure of the gas, P1 = 294 kPa

Final pressure of the gas, P2 = 500 kPa

Initial temperature of the gas, T1 = 100° C = 100 + 273 K = 373 K

Final temperature of the gas, T2 = ?

Let us assume that the gas is an ideal gas, then we use the equation below to solve

T2/T1 = P2/P1

T2 = T1 * (P2/P1)

T2 = (100 + 273) * (500 / 294)

T2 = 373 * (500 / 294)

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T2 = 634 K

T2 = 634 K - 273 K = 361° C

5 0
3 years ago
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