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NemiM [27]
3 years ago
9

How do you find the total number of nodes in a two-source interference pattern?

Physics
1 answer:
hodyreva [135]3 years ago
8 0
The distance between two nodes is HALF the wavelength. So if the wavelength is 2cm the distance between two adjacent nodes is 1 cm. does this help?
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Heeeeelllppp meeeeee. I have an eaxaammm
Readme [11.4K]

Answer:

Explanation: Its your hairline

hahahahah

5 0
3 years ago
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A disk, initially rotating at 120 rpm, is slowed down with a constant acceleration of magnitude 4 rad s2. If the disk has diamet
andrey2020 [161]

Answer:

Explanation:

given,

ω₁ = 120 rpm

        1 rpm = \dfrac{2\pi }{60} rad/s

         \omega_1 =120\times \dfrac{2\pi }{60} rad/s

                          = 12.56 rad/s

α = - 4 rad/s²

diameter of disk = 20 cm

final angular velocity = 0

t = \dfrac{\omega_f-\omega_i}{\alpha}

t = \dfrac{0-(12.56)}{-4}

t = 3.14 s.

2) \theta = \omega_i t +\dfrac{1}{2} \alpha t^2

              =  12.56\times 3.14 +\dfrac{1}{2}\times (-4)\times 3.14^2

              = 19. 72 radians

3) total angular distance rotated

x = θ R

x = 19.72 × 0.1 = 1.97 m

x = 2 m

3 0
3 years ago
A 65kg person throw a 0.045kg snowball forward with a ground speed of 30m/s. A second person, with a mass of 60kg, catches the s
Kobotan [32]
Well, st first we should find <span>initial momentum for the first person represented in the task which definitely must be :
</span>(65+0.045)*2.5
And then we find the final one :  65*x + 0.045*30
Then equate them together : x=2.48 m/s 
So we can get the velocity, which is is 2.48 m/s
In that way, according to the main rules of <span>conservation of momentum you can easily find the solution for the second person.
Regards!</span>
6 0
4 years ago
The umbra during a SOLAR OR LUNAR eclipse is smaller than during a SOLAR OR LUNAR eclipse.
skad [1K]
The umbra during a solar eclipse is smaller than during a lunar eclipse.
3 0
3 years ago
If a bird were to start out from the origin (where the student starts) and fly directly (in a straight line) to the school, what
REY [17]

The question is incomplete! The complete question along with answer and explanation is provided below.

Question:

A student bikes to school by traveling first 1.00 miles north, then 0.500 miles west and finally 0.200 miles south.

If a bird were to start out from the origin (where the student starts) and fly directly (in a straight line) to the school, what distance db would the bird cover

Given Information:  

distance towards north = dn =  1.00 mi

distance towards west = dw =  0.500 mi

distance towards south = ds =  0.200 mi

Required Information:  

distance covered by bird = db = ?

Answer:

distance covered by bird = 0.94 miles

Explanation:

As you can see in the attached image, by applying the Pythagoras theorem,

db = √(dn - ds)² + dw²

db = √ (1.0 - 0.20)² + 0.50²

db = √ 0.80² + 0.50²

db = 0.94 miles

Therefore, the bird would cover a distance of 0.94 miles

5 0
3 years ago
Read 2 more answers
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