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victus00 [196]
3 years ago
7

Einstein and lorentz, being avid tennis players, play a fast-paced game on a court where they stand 19.0 m from each other. bein

g very skilled players, they play without a net. the tennis ball has mass 0.0580 kg. you can ignore gravity and assume that the ball travels parallel to the ground as it travels between the two players. unless otherwise specified, all measurements are made by the two men.
Physics
1 answer:
Dvinal [7]3 years ago
7 0
So sometimes when you actually do you work it’s happens and you get answers idk about that
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The two types of vitamins are fat and water soluble?
lianna [129]
Its true hopefully this helps you.
4 0
3 years ago
In the following figure, if AB ǁ CD, then find the measure of PCD and CPD.​
mina [271]

Answer:

CPD = 80

PCD = 44

Explanation:

Given

AB || CD

BAD = 56

CPA = 100

See attachment

Required

Determine PCD and CPD

First, we need to calculate CPD

Since DPA is a straight line and CPA = 100;

We have that:

CPA + CPD = 180 --- angle on a straight theorem

Substitute 100 for CPA

100 + CPD = 180

Subtract 100 from both sides

100-100 + CPD = 180-100

CPD = 80

Next, we calculate PCD

We have that:

DAB= ADC = 56  --alternate angle

In triangle PCD

PCD + CPD + PDC = 180 --- angles in a triangle

Where

PDC = ADC = 56

So, we have:

PCD +80 + 56 = 180

PCD +136 = 180

Subtract 136 from both sides

PCD = 180 - 136

PCD = 44

6 0
3 years ago
Sketch the resultant field pattern around the following current carrying conductors and
Novay_Z [31]
Cccccccvvvvvcjjjjjjjjjjkllk ki e
8 0
3 years ago
A vector A has a magnitude of 5 units and points in the −y-direction, while a vector B has triple the magnitude of A and points
Harman [31]

Answer:

A+B; 5√5 units, 341.57°

A-B; 5√5 units, 198.43°

B-A; 5√5 units, 18.43°

Explanation:

Given A = 5 units

By vector notation and the axis of A, it is represented as -5j

B = 3 × 5 = 15 units

Using the vector notations and the axis, B is +15i. The following vectors ate taking as the coordinates of A and B

(a) A + B = -5j + 15i

A+B = 15i -5j

|A+B| = √(15)²+(5)²

= 5√5 units

∆ = arctan(5/15) = 18.43°

The angle ∆ is generally used in the diagrams

∆= 18.43°

The direction of A+B is 341.57° based in the condition given (see attachment for diagrams

(b) A - B = -5j -15i

A-B = -15i -5j

|A-B|= √(15)²+(-5)²

|A-B| = √125

|A-B| = 5√5 units

The direction is 180+18.43°= 198.43°

See attachment for diagrams

(c) B-A = 15i -( -5j) = 15i + 5j

|B-A| = 5√5 units

The direction is 18.43°

See attachment for diagram

5 0
3 years ago
Heat energy can be transferred from a source to a receiver by I. radiation. II. convection. III. conduction. A.
nadya68 [22]
It can be transferred by I, II, and III




Hope this helps ! :}
7 0
3 years ago
Read 2 more answers
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