The best and most correct answer among the choices provided by the question is <span>D.The radioactive decay of an atom</span> <span>.
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Answer: Units: C, T and Variables: <em>c, C, t, T</em>
(a) C is the unit of charge Coulomb, (e) T is the unit of magnetic field strength Tesla.
In physics, units are written straight and variables are written in italics. Various italic symbols are used for various quantities like <em>t </em>for time, <em>T</em> for temperature, <em>c</em> for any constant and <em>C</em> for curie constant.
Explanation:
P = F/A
P = mg/A [ since F = mg ]
P = Vdg/A [ since m = Vd ]
P = Ahdg/A [ since V = Ah ]
P = hdg
The three parts of the Earth are Atmosphere, Hydrosphere and Lithosphere.
Atmosphere is the blanket of air that surrounds the earth. It is densest close to the surface and thins out as one moves higher. Atmosphere of Earth contains mainly Nitrogen, followed by Oxygen and small amounts of water vapor, Carbondioxide and other gases.
Lithosphere is the outer most part of the earth's surface. The Earth's crust and the mantle form Lithosphere.
Hydrosphere is the part of the Earth that has water. The Oceans, seas, rivers, lakes and other water bodies constitute the Hydrosphere.
Stratosphere, Mesosphere and Ionosphere are different layers of atmosphere.
Hence, for the study of the Earth, one needs to consider earth to be made of three parts- atmosphere, Lithosphere and Hydrosphere.
Kinetic energy = (1/2) (mass) x (speed)²
At 7.5 m/s, the object's KE is (1/2) (7.5) (7.5)² = 210.9375 joules
At 11.5 m/s, the object's KE is (1/2) (7.5) (11.5)² = 495.9375 joules
The additional energy needed to speed the object up from 7.5 m/s
to 11.5 m/s is (495.9375 - 210.9375) = <em>285 joules</em>.
That energy has to come from somewhere. Without friction, that's exactly
the amount of work that must be done to the object in order to raise its
speed by that much.
