Answer:
This is TRUE
Explanation:
The tree can fall down even though no one did anything to it...
A hard breeze can blow and it can fall down or something else can cause it to topple...
Not only humans can make trees topple over...
<em>PLEASE</em><em> </em><em>DO MARK</em><em> </em><em>ME AS</em><em> </em><em>BRAINLIEST UWU</em><em> </em>
<em>Bonne journée</em><em> </em><em>;</em><em>)</em><em> </em>
Answer:
period of oscillations is 0.695 second
Explanation:
given data
mass m = 0.350 kg
spring stretches x = 12 cm = 0.12 m
to find out
period of oscillations
solution
we know here that force
force = k × x .........1
so force = mg = 0.35 (9.8) = 3.43 N
3.43 = k × 0.12
k = 28.58 N/m
so period of oscillations is
period of oscillations = 2π ×
................2
put here value
period of oscillations = 2π ×
period of oscillations = 0.6953
so period of oscillations is 0.695 second
Answer:
61.33 Kg
Explanation:
From the question given above, the following data were obtained:
Distance = 1×10² m
Time = 9.5 s
Kinetic energy (KE) = 3.40×10³ J
Mass (m) =?
Next, we shall determine the velocity Leroy Burrell. This can be obtained as follow:
Distance = 1×10² m
Time = 9.5 s
Velocity =?
Velocity = Distance / time
Velocity = 1×10² / 9.5
Velocity = 10.53 m/s
Finally, we shall determine the mass of Leroy Burrell. This can be obtained as follow:
Kinetic energy (KE) = 3.40×10³ J
Velocity (v) = 10.53 m/s
Mass (m) =?
KE = ½mv²
3.40×10³ = ½ × m × 10.53²
3.40×10³ = ½ × m × 110.8809
3.40×10³ = m × 55.44045
Divide both side by 55.44045
m = 3.40×10³ / 55.44045
m = 61.33 Kg
Thus, the mass of Leroy Burrell is 61.33 Kg
Answer:
The fastest satellite must change orbit
The most massive body (m₁) transfers more momentum to the satellite,
Explanation:
For this problem we consider a system formed by the satellite and each of the bodies with which it collides, in this system the forces during the collision are internal, the amount of movement must be conserved. Let's write the momentum is two instants
Most massive body (m1)
initial. Before the crash
p₀₁ = M v + m₁ v₁
after the crash
= M v´ + m₁ v₁´
how momentum is conserved
p₀ = p_{f}
Lighter body (m2)
p₀₂ = M v + m₂ v₂
p_{f2} = M v´ + m₂ v₂´
Let's clarify that the speed of the satellite and the object do not have the same direction, in general these shocks are elastic.
We can see that p₀₁> p₀₂
Let us analyze the two cases when the body collides, The most massive body (m₁) transfers more momentum to the satellite, therefore there must be a greater change in its momentum and velocity.
The fastest satellite must change orbit, thus rotating at a different distance from Earth