A car of mass 750 kg has an initial speed of 75 mph. Traveling in a straight line, its speed is increased uniformly to 120 mph i
1 answer:
Explanation:
ESTE PROBLEMA ES MEJOR HACERLO EN SI. PRIMERO CONVIERTES
LA VELOCIDAD INICIAL Y LA VELOCIDAD FINAL A m/s
= 33.52 m/s <em>v</em> = 53.67 m/s <em>x</em> = 3220 m
PRIMERO ENCUENTRAS LA ACELERACIÓN DEL COCHE CON LA ECUACIÓN
DE GALILEO GALILEI
<em>a</em> = =
AHORA CON LA ACELERACIÓN USMOS LA SEGUNDA LEY DE NEWTON
F = 75 kg() = 40.9 N
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Answer:
The average power delivered by the elevator motor during this period is 6.686 kW.
Explanation:
Given;
mass of the elevator, m = 636 kg
initial speed of the elevator, u = 0
time of motion, t = 4.5 s
final speed of the elevator, v = 2.05 m/s
The upward force of the elevator is calculated as;
F = m(a + g)
where;
m is mass of the elevator
a is the constant acceleration of the elevator
g is acceleration due to gravity = 9.8 m/s²
F = (636)(0.456 + 9.8)
F = (636)(10.256)
F = 6522.816 N
The average power delivered by the elevator is calculated as;
Therefore, the average power delivered by the elevator motor during this period is 6.686 kW.
Answer:
R = 1.2295 10⁵ m
Explanation:
After reading your problem they give us the diameter of the lens d = 4.50 cm = 0.0450 m, therefore if we use the Rayleigh criterion for the resolution in the diffraction phenomenon, we have that the minimum separation occurs in the first minimum of diffraction of one of the bodies m = 1 coincides with the central maximum of the other body
θ = 1.22 λ / D
where the constant 1.22 leaves the resolution in polar coordinates and D is the lens aperture
how angles are measured in radians
θ = y / R
where y is the separation of the two bodies (bulbs) y = 2 m and R the distance from the bulbs to the lens
R =
let's calculate
R =
R = 1.2295 10⁵ m