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BabaBlast [244]
2 years ago
5

A car of mass 750 kg has an initial speed of 75 mph. Traveling in a straight line, its speed is increased uniformly to 120 mph i

n 2.0 miles. What is the net force that was exerted?
Physics
1 answer:
mr_godi [17]2 years ago
6 0

Explanation:

ESTE PROBLEMA ES MEJOR HACERLO EN SI. PRIMERO CONVIERTES

LA VELOCIDAD INICIAL Y LA VELOCIDAD FINAL A m/s

v_{0} = 33.52 m/s      <em>v</em> = 53.67 m/s      <em>x</em> = 3220 m

PRIMERO ENCUENTRAS LA ACELERACIÓN DEL COCHE CON LA ECUACIÓN

DE GALILEO GALILEI

<em>a</em> = (53.67 m/s)^{2} - (33.52 m/s)^{2}/3220 m = 0.5453 m/s^{2}

AHORA CON LA ACELERACIÓN USMOS LA SEGUNDA LEY DE NEWTON

F = 75 kg(0.5453 m/s^{2}) = 40.9 N

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2. the dipole moment of a dipole in a 300-n/c electric field is initially perpendicular to the field, but it rotates so it is in
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<h3>What is Electric dipole?</h3>

A pair of opposite, non-coplanar, equally powerful electric charges that are in opposition to one another. An atom is said to have a "induced electric dipole" if the center of the negative cloud of electrons has moved a little bit away from the nucleus due to an external electric field. When the external field is taken away, dipolarity is lost.

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Solution:

From the formula we know.

U = -pE cosФ

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p Denotes Dipole moment.

E Denotes Electric field.

Ф Denotes angle b/w them

Now, as given, firstly the dipole is perpendicular to the electric field, so

angle (Ф1) will be 90° and now the dipole is rotated such that they are in same

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So, let's find Change in Potential energy which will be equal to the work done

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ΔU = [-pE*cos Ф2] - [-pE *cos Ф1]

ΔU = [-pE*cos Ф2] + pE *cos Ф1

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Substituting the values,

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ΔU = 6 x 10^-7

W = ΔU = -6 x 10^-7

W = - 6 x 10 7 J

Work Done (W) by the field is - 6 x 10-7 J.

To learn more about Work Done visit:

https://brainly.in/question/48222628

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