A car of mass 750 kg has an initial speed of 75 mph. Traveling in a straight line, its speed is increased uniformly to 120 mph i
1 answer:
Explanation:
ESTE PROBLEMA ES MEJOR HACERLO EN SI. PRIMERO CONVIERTES
LA VELOCIDAD INICIAL Y LA VELOCIDAD FINAL A m/s
= 33.52 m/s <em>v</em> = 53.67 m/s <em>x</em> = 3220 m
PRIMERO ENCUENTRAS LA ACELERACIÓN DEL COCHE CON LA ECUACIÓN
DE GALILEO GALILEI
<em>a</em> = =
AHORA CON LA ACELERACIÓN USMOS LA SEGUNDA LEY DE NEWTON
F = 75 kg() = 40.9 N
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Answer:
The velocity of the cart at the bottom of the ramp is 1.81m/s, and the acceleration would be 3.30m/s^2.
Explanation:
Assuming the initial velocity to be zero, we can obtain the velocity at the bottom of the ramp using the kinematics equations:
Dividing the second equation by the first one, we obtain:
And, since , then:
It means that the velocity at the bottom of the ramp is 1.81m/s.
We could use this data, plus any of the two initial equations, to determine the acceleration:
So the acceleration is 3.30m/s^2.
Answer:
The acceleration of the car will be
Explanation:
We have given that distance from stop sign s = 200 m
Time t = 0.2 sec
We have to find the constant acceleration
Now from second equation of motion
So the acceleration of the car will be