Question

Find the product. (n + 8)(n - 2)

Answer 1

$(a+b)(c-d)=ac+cb-bd-da\\(n+8)(n-2)=\\(n\times n)+(n\times8)-(8\times2)-(2\times n)\\n^2+8n-16-2n\\{\boxed{n^2+6n-16}$

Answer 2

If you would like to find the product (n + 8) * (n - 2), you can do this using the following steps:

(n + 8) * (n - 2) = n * n - 2 * n + 8 * n - 8 * 2 = n^2 + 6 * n - 16

The correct result would be n^2 + 6 * n - 16.