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3 years ago

Please helpppp!?!!!!?

Mathematics

2 answers:

Bad White [126]3 years ago

7 0

I Think Its 9... (Not Really Sure Tho)

____ [38]3 years ago

3 0

It would be 9!!!
Hope that helps!!!

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Determine the intercepts of the line.<br> - 4x + 7 = 2y - 3

Bingel [31]

-4x+7=2y-3
Put this in y=mx+b
-4x+10=2y
Switch it around
2y=10-4x
Put it in y=mx+b
2y=-4x+10
Divide by 2
y=-2x+5

5 0

3 years ago

It is possible to measure the length of a ____

crimeas [40]

Answer:

a line segment

Step-by-step explanation:

a line and a ray cannot be measured because they move infinity in one or both directions

7 0

4 years ago

Read 2 more answers

Can someone help please!

GarryVolchara [31]

This is for the first one

6 0

3 years ago

Solve the system of equations by graphing

Rudik [331]

Answer:

Step-by-step explanation:

3 0

3 years ago

Use Definition 7.1.1, DEFINITION 7.1.1 Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = ∞ e−

poizon [28]

$f(t)=\begin{cases}\cos t&\text{for }0\le t$

The Laplace transform is then

$\mathcal L_s\{f(t)\}=\displaystyle\int_0^\infty f(t)e^{-st}\,\mathrm dt=\int_0^\pi e^{-st}\cos t\,\mathrm dt$

Let $I$ denote the integral we want to compute. Integrating by parts, setting

$u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt$

$\mathrm dv=\cos t\,\mathrm dt\implies v=\sin t$

gives

$\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\int_0^\pi e^{-st}\sin t\,\mathrm dt$

Integrate by parts again, setting

$u=e^{-st}\implies\mathrm du=-se^{-st}\,\mathrm dt$

$\mathrm dv=\sin t\,\mathrm dt\implies v=-\cos t$

Then

$\displaystyle I=e^{-st}\sin t\bigg|_{t=0}^{t=\pi}+s\left(-e^{-st}\cos t\bigg|_{t=0}^{t=\pi}-s\int_0^\pi e^{-st}\cos t\,\mathrm dt\right)$

$I=e^{-st}(\sin t-s\cos t)\bigg|_{t=0}^{t=\pi}-s^2I$

$(s^2+1)I=s(e^{-\pi s}+1)$

$I=\dfrac s{s^2+1}(e^{-\pi s}+1)$

7 0

4 years ago