Answer:
y = 4x + 8
Step-by-step explanation:
1) Find slope:
y2-y1/x2-x1
12-8/1-0 = 4/1 = 4
Slope = 4
2) Plug in a point in point-slope form
y-y1=m(x-x1)
y-8=4(x-0) =
y-8=4x-0 -> add 8 to both sides
y=4x+8
Answer:
60 kilometers per hour (kmph) over the limit
Step-by-step explanation:
The speed limit is 60 kmph
Let's find his original rate:
We know D = RT
Where
D is the distance, in km
R is the rate, in kmph
T is the time in hours
He went 10 km in 5 minutes, so we need the time in hours, first. That would be:
5/60 = 1/12 hour
So, putting into formula, we find rate:
D = RT
10 = R(1/12)
R = 10/(1/12)
R = 10 * 12
R = 120 kmph
He was going over by:
120 - 60 = 60 kmph
Answer:
c
Step-by-step explanation:
The area of D is given by:
The average value of f over D is given by:
![\frac{1}{ \frac{343}{3} } \int\limits^7_0 \int\limits^{x^2}_0 {4x\sin(y)} \, dydx = -\frac{3}{343} \int\limits^7_0 {4x\cos(x^2)} \, dx \\ \\ =-\frac{3}{343} \int\limits^{49}_0 {2\cos(t)} \, dt=-\frac{6}{343} \left[\sin(t)\right]_0^{49} \, dt=-\frac{6}{343}\sin49](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%20%5Cfrac%7B343%7D%7B3%7D%20%7D%20%20%5Cint%5Climits%5E7_0%20%20%5Cint%5Climits%5E%7Bx%5E2%7D_0%20%7B4x%5Csin%28y%29%7D%20%5C%2C%20dydx%20%20%3D%20-%5Cfrac%7B3%7D%7B343%7D%20%20%5Cint%5Climits%5E7_0%20%7B4x%5Ccos%28x%5E2%29%7D%20%5C%2C%20dx%20%20%5C%5C%20%20%5C%5C%20%3D-%5Cfrac%7B3%7D%7B343%7D%20%5Cint%5Climits%5E%7B49%7D_0%20%7B2%5Ccos%28t%29%7D%20%5C%2C%20dt%3D-%5Cfrac%7B6%7D%7B343%7D%20%5Cleft%5B%5Csin%28t%29%5Cright%5D_0%5E%7B49%7D%20%5C%2C%20dt%3D-%5Cfrac%7B6%7D%7B343%7D%5Csin49)
Answer:
8.36
Step-by-step explanation:
