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larisa86 [58]
4 years ago
14

Nitroglycerine decomposes violently according to the chemical equation below. What mass of carbon dioxide gas is produced from t

he decomposition of 13.3 g C3H5(NO3)3? 4 C3H5(NO3)3() → 12 CO2(g) + 6 N2(g) +10 H2O(g) + O2(g)
Chemistry
1 answer:
AveGali [126]4 years ago
4 0

Answer : The mass of CO_2  produced is, 7.74 grams

Solution : Given,

Mass of C_3H_5(NO_3)_3 = 13.3 g

Molar mass of C_3H_5(NO_3)_3 = 227 g/mole

Molar mass of CO_2 = 44 g/mole

First we have to calculate the moles of C_3H_5(NO_3)_3.

\text{ Moles of }C_3H_5(NO_3)_3=\frac{\text{ Mass of }C_3H_5(NO_3)_3}{\text{ Molar mass of }C_3H_5(NO_3)_3}=\frac{13.3g}{227g/mole}=0.0586moles

Now we have to calculate the moles of CO_2

The balanced chemical reaction is,

4C_3H_5(NO_3)_3\rightarrow 12CO_2(g)+6N_2(g)+10H_2O(g)+O_2(g)

From the reaction, we conclude that

As, 4 mole of C_3H_5(NO_3)_3 react to give 12 mole of CO_2

So, 0.0586 moles of C_3H_5(NO_3)_3 react to give 0.0586\times \frac{12}{4}=0.176 moles of CO_2

Now we have to calculate the mass of CO_2

\text{ Mass of }CO_2=\text{ Moles of }CO_2\times \text{ Molar mass of }CO_2

\text{ Mass of }CO_2=(0.176moles)\times (44g/mole)=7.74g

Thus, the mass of CO_2  produced is, 7.74 grams

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