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allsm [11]
3 years ago
13

Coal, which is primarily carbon, can be converted to natural gas, primarily CH4, by the following exothermic reaction: C(s)+2H2(

g)⇌CH4(g) A. What is the effect of adding more C to the reaction mixture? B. What is the effect of adding more H2 to the reaction mixture? C. What is the effect of raising the temperature of the reaction mixture? D. What is the effect of lowering the volume of the reaction mixture? E. What is the effect of adding a catalyst to the reaction mixture? F. Which of the following will favor CH4 at equilibrium?
catalyst to the reaction mixture", "raising the temperature of the reaction mixture", "both adding more H2 to the reaction mixture and lowering the volume of the reaction mixture", "adding more C to the reaction mixture"]
Chemistry
1 answer:
LuckyWell [14K]3 years ago
4 0

Answer:

A. The reaction will proceed forward forming more CH4

B. The reaction will proceed forward forming more CH4

C. Since the reaction is exothermic, raising the temperature will cause the reaction to proceed backward, thus forming C and H2.

D. Lowering the volume makes the gas particles to be more close together thereby enhancing their collisions leading to reaction. Therefore the reaction will proceed forward forming more CH4

E. Catalyst only reduce the activation energy so the reaction can proceed faster. The reaction will proceed forward forming.

F. The following will favour CH4 at equilibrium

i. Catalyst to the reaction mixture,

ii. Both adding more H2 to the reaction mixture and lowering the volume of the reaction mixture

iii. Adding more C to the reaction mixture.

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dybincka [34]

<u>Answer:</u> The electronic configuration of the elements are written below.

<u>Explanation:</u>

Electronic configuration is defined as the representation of electrons around the nucleus of an atom.

Number of electrons in an atom is determined by the atomic number of that atom.

For the given options:

  • <u>Option a:</u>  Carbon (C)

Carbon is the 6th element of the periodic table. The number of electrons in carbon atom are 6.

The electronic configuration of carbon is 1s^22s^22p^2

  • <u>Option b:</u>  Phosphorus (P)

Phosphorus is the 15th element of the periodic table. The number of electrons in phosphorus atom are 15.

The electronic configuration of phosphorus is 1s^22s^22p^63s^23p^3

  • <u>Option c:</u>  Vanadium (V)

Vanadium is the 23rd element of the periodic table. The number of electrons in vanadium atom are 23.

The electronic configuration of vanadium is 1s^22s^22p^63s^23p^64s^23d^3

  • <u>Option d:</u>  Antimony (Sb)

Antimony is the 51st element of the periodic table. The number of electrons in antimony atom are 51.

The electronic configuration of antimony is 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^3

  • <u>Option e:</u>  Samarium (Sm)

Samarium is the 62nd element of the periodic table. The number of electrons in samarium atom are 62.

The electronic configuration of samarium is 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^24f^6

Hence, the electronic configuration of the elements are written above.

4 0
3 years ago
What are the branch-chain Alkanes?
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The top branch-chain is a Isobutane branch. And the bottom branch chain is a  Neopentane branch

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An unknown liquid has a mass of 30.8 g, and a volume of 31.5 mL. What is the density of this liquid?
julsineya [31]

The density of the liquid is 0.98 g/mL

<h3>What is density? </h3>

The density of a substance is defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as:

Density = mass / volume

With the above formula, we can obtain the density of the liquid.

<h3>How to determine the density </h3>
  • Mass = 30.8 g
  • Volume = 31.5 mL
  • Density =?

Density = mass / volume

Density of liquid = 30.8 / 31.5

Density of liquid = 0.98 g/mL

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Answer:

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The quantity, 1,385 mg is equivalent to in scientific notation
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Answer:

The answer is 1385 x10∧ -3

Explanation:

Scientific notation is a quick way to represent a number using notation in exponential form or powers of base ten.

This notation allows us to express too large or small numbers easily.

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500 is written as 5x10∧2; Where the power 2 represents the number of 0's that follow 5.

0.0093 is written as 9.3x10∧-3; Where the power -3 represents the number of times the comma was moved to the right.

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