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allsm [11]
3 years ago
13

Coal, which is primarily carbon, can be converted to natural gas, primarily CH4, by the following exothermic reaction: C(s)+2H2(

g)⇌CH4(g) A. What is the effect of adding more C to the reaction mixture? B. What is the effect of adding more H2 to the reaction mixture? C. What is the effect of raising the temperature of the reaction mixture? D. What is the effect of lowering the volume of the reaction mixture? E. What is the effect of adding a catalyst to the reaction mixture? F. Which of the following will favor CH4 at equilibrium?
catalyst to the reaction mixture", "raising the temperature of the reaction mixture", "both adding more H2 to the reaction mixture and lowering the volume of the reaction mixture", "adding more C to the reaction mixture"]
Chemistry
1 answer:
LuckyWell [14K]3 years ago
4 0

Answer:

A. The reaction will proceed forward forming more CH4

B. The reaction will proceed forward forming more CH4

C. Since the reaction is exothermic, raising the temperature will cause the reaction to proceed backward, thus forming C and H2.

D. Lowering the volume makes the gas particles to be more close together thereby enhancing their collisions leading to reaction. Therefore the reaction will proceed forward forming more CH4

E. Catalyst only reduce the activation energy so the reaction can proceed faster. The reaction will proceed forward forming.

F. The following will favour CH4 at equilibrium

i. Catalyst to the reaction mixture,

ii. Both adding more H2 to the reaction mixture and lowering the volume of the reaction mixture

iii. Adding more C to the reaction mixture.

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Calculate the energy required to heat 322.0g of ethanol from −2.2°C to 19.6°C . Assume the specific heat capacity of ethanol und
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Answer:

There is 17.1 kJ energy required

Explanation:

Step 1: Data given

Mass of ethanol = 322.0 grams

Initial temperature = -2.2 °C = 273.15 -2.2 = 270.95K

Final temperature = 19.6 °C = 273.15 + 19.6 = 292.75 K

Specific heat capacity = 2.44 J/g*K

Step 2: Calculate energy

Q = m*c*ΔT

⇒ m = the mass of ethanol= 322 grams

⇒ c = the specific heat capacity of ethanol = 2.44 J/g*K

⇒ ΔT = T2 - T1 = 292.75 - 270.95 = 21.8 K

Q = 322 * 2.44 * 21.8 = 17127.8 J = 17.1 kJ

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First, we write the balanced equation for this reaction:

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