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Maksim231197 [3]
2 years ago
13

The enthalpy of reaction is −2202.0 kJ/mol. How much energy (in joules) will be released if 65.98 grams of propane is burned. (M

olar mass of propane = 44.11 g/mol). Record your answer in scientific notation using 3 significant figures.
The combustion of propane is given by the following reaction.

C3H8+3O2→3CO2+4H2O
Chemistry
1 answer:
m_a_m_a [10]2 years ago
6 0

Answer:very old tftp

Explanation:

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Hey please answer this for me thanks.
Aleks [24]

Explanation:

Moles of N2 = 84/28 = 3.0mol

Moles of H2 = 29/2 = 14.5mol

Hence amount of ammonia produced = 6.0 * 17 = 102g.

7 0
3 years ago
What is the volume of an 2.3 solution with 212 grams of calcium chloride dissolved in it
Travka [436]

830 mL. A 2.3 mol/L solution of CaCl2 has a volume of 830 mL

I am guessing that the concentration of your solution is 2.3 mol/L.

a) Moles of CaCl2

MM of CaCl2 = 110.98 g/mol

Moles of CaCl2 = 212 g CaCl2 x (1 mol CaCl2/110.98 g CaCl2)

= 1.910 mol CaCl2

b) Volume of solution

V = 1.910 mol CaCl2 x (1 L solution/2.3 mol CaCl2) = 0.83 L solution

= 830 mL solution


5 0
3 years ago
Use the periodic table to choose the correct name for each of the following substances. Check all tha
Vinvika [58]

Answer:

phosphorus trichloride

8 0
3 years ago
Which characteristic is a property of water?
Anettt [7]
D.
The main properties of water are its polarity, cohesion, adhesion, surface tension, high specific heat, and evaporative cooling.
7 0
2 years ago
You have a ballon filled with hydrogen gas which keeps it at a constant pressure, regardless the volume. The initial volume of t
abruzzese [7]

Answer:

619°C

Explanation:

Given data:

Initial volume of gas = 736 mL

Initial temperature = 15.0°C

Final volume of gas = 2.28 L

Final temperature = ?

Solution:

Initial volume of gas = 736 mL (736mL× 1L/1000 mL = 0.736 L)

Initial temperature = 15.0°C (15+273 = 288 K)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = T₁V₂/V₁  

T₂ = 2.28 L × 288 K / 0.736 L

T₂ = 656.6 L.K / 0.736 L

T₂ = 892.2 K

K to °C:

892.2 - 273.15 = 619°C

7 0
2 years ago
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