The volume occupied by the argon gas is, 1.44 L
Explanation :
To calculate the volume of argon gas we are using ideal gas equation:
where,
P = pressure of argon gas = 1528 torr = 2.010 atm
Conversion used : (1 atm = 760 torr)
V = volume of argon gas = ?
T = temperature of argon gas = 
R = gas constant = 0.0821 L.atm/mole.K
w = mass of argon gas = 4.24 g
M = molar mass of argon gas = 39.95 g/mole
Now put all the given values in the ideal gas equation, we get:
Therefore, the volume of occupied by argon gas is 1.44 L
Answer:
Its C I hopefully help you
Uhm I think 5 sorry if I’m wrong
Answer:
a) 
b) 
is the limiting reagent
c) Moles of 
produced = 2.45 mol
b) Moles of 
left = 1.75 -1.22 = 0.53
Explanation:
a) Balanced reaction:
b)
No. of mole of 
No. of mole of 
As, it is clear from the reaction that,
1 mol of requires 3 moles of
1.75 mol of require = 1.75 × 3 = 5.25 mol of
As, only 3.68 mol of is present, so is the limiting reagent.
c)
3 moles of form 2 moles of 
3.68 moles of will form = 
d)
is present in excess.
3 moles of requires 1 mol of
3.68 moles of will require = 
left = 1.75 -1.22 = 0.53 mol
