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arsen [322]
3 years ago
5

2x + y - z = 3 -x + 2y + 4z = -3 x – 2y - 3z = 4

Mathematics
2 answers:
nika2105 [10]3 years ago
7 0

Answer:

x = 3; y = -2; z = 1.

Step-by-step explanation:

-x + 2y + 4z = -3

x – 2y - 3z = 4

(-x + x) + (2y - 2y) + (4z - 3z) = (-3 + 4)

0 + 0 + z = 1

z = 1

x - 2y - 3(1) = 4

x - 2y - 3 = 4

x - 2y = 7

x = 2y + 7

2(2y + 7) + y - (1) = 3

4y + 14 + y - 1 = 3

5y + 13 = 3

5y = -10

y = -2

x = 2(-2) + 7

x = -4 + 7

x = 3

So, your answer is (3, -2, 1).

Hope this helps!

mario62 [17]3 years ago
4 0

Answer:

x=3, y=-2, z=1

Step-by-step explanation:

I solved by substitution

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What is a35 for the arithmetic sequence presented in the table below?
Kryger [21]

Answer: choice B) a35 = -118

=====================================================

Explanation:

When n = 5, an = 32 as shown in the first column of the table. This means the fifth term is 32. Plug in those values to get

an = a1+d(n-1)

32 = a1+d(5-1)

32 = a1+4d

Solve for a1 by subtracting 4d from both sides

a1 = 32-4d

We'll plug this in later

Turn to the second column of the table. We have n = 10 and an = 7. Plug those values into the formula

an = a1+d(n-1)

7 = a1 + d(10-1)

7 = a1+9d

Now substitute in the equation in which we solved for a1

7 = a1+9d

7 = 32-4d+9d ... replace a1 with 32-4d

7 = 32+5d

5d = 7-32

5d = -25

d = -25/5

d = -5

This tells us that we subtract 5 from each term to get the next term.

Use this d value to find a1

a1 = 32-4d

a1 = 32-4*(-5)

a1 = 32+20

a1 = 52

The first term is 52

--------------

The nth term formula is therefore

an = 52 + (-5)(n-1)

which simplifies to

an = -5n + 57

To check this result, plug in n = 5 to find that a5 = 32. Similarly, you'll find that a10 = 7 after plugging in n = 10. I'll let you do these checks.

--------------

Replace n with 35 to find the 35th term

an = -5n + 57

a35 = -5(35) + 57

a35 = -175 + 57

a35 = -118

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Answer:

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