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kaheart [24]
4 years ago
15

An object when orbiting the Earth at a height of three Earth radii from the center of the Earth has a weight of 1.00 N. What is

the object’s mass? (g at the surface of the Earth is 9.8 m/s^2)
Physics
1 answer:
zaharov [31]4 years ago
5 0

Answer:0.918 kg

Explanation:

Given

Object is at a distance of r=3 R from earth surface

where R=radius of Earth

acceleration due to Gravity is given by

g=\frac{Gm_e}{R^2}

at earth surface g=9.8 m/s^2

g at r=3 R

g'=\frac{Gm_e}{(3R)^2}

g'=\frac{Gm_e}{9R^2}

g'=\frac{g}{9}

Weight at r=3R is 1 N

thus Weight at Earth surface will be 9 times at r=3R

weight at  Earth surface =9 N

mass=\frac{9}{9.8}=0.918 kg

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The current in a resistor is 2.0 A, and its power is 78 W. What is the voltage?
bazaltina [42]

Answer:

39 volts

Explanation:

Use the equation P=VI

78=V(2)

V=39

6 0
3 years ago
A naked, male corpse was found at 8AM on Tuesday, July 9.The air temperature wasalready 26.7˚C (81˚F). The body exhibited some s
Slav-nsk [51]

Answer:

x = 9.87 hours ago.

Further explanation is present below.

Explanation:

Data given:

Air Temperature = 26.7°C (81°F)

Body temperature = 34.4°C (93.9°F)

We are given that, Livor mortis was absent. Secondly, The body exhibited some stiffness in the face and eyelids.

So, it can be concluded that, body must have died recently, as Livor mortis was absent plus the presence of stiffness in the face and eyelids. Furthermore,

The normal body temperature = 37°C

Body temperature in our case = 34.4° C

Difference = 37 -34.4 = 2.6°C

And Air temperature = 26.7°C

Which is a very low difference, in addition, it has not acquired the air temperature so, all this evidence certifies that body died recently.

Now, we have to calculate, how recently it died.

Formula:

0.78 . x = difference of body temperature and air temperature

Where, x = number of hours = time required,

0.78 . x = (34.4 - 26.7)

0.78 . x = 7.7

x = 7.7/0.78

x = 9.87 hours ago.

It means that, naked male corpse was died 9.87 hours ago.

Now, we are asked to find out clothing on the body had made a difference or not.

So, Yes it would definitely make a difference. As body would have more warmer than being naked. and it would result in a calculation of a different time of death. (body temperature would have > 34.4°C)

3 0
3 years ago
Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th
DiKsa [7]

Answer:

a.\rm -1.49\ m/s^2.

b. \rm 50.49\ m.

Explanation:

<u>Given:</u>

  • Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

<h2>(a):</h2>

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).

At time t = 3 seconds,

\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

<h2>(b):</h2>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.

For the time interval of 2 seconds,

\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.

It is the displacement of the particle in 2 seconds.

7 0
4 years ago
What happens to the distance physics help please? The frequency of a wave increases. What happens to the distance between succes
aliya0001 [1]
For any periodic wave 
<span>v = f λ </span>

<span>where </span>
<span>v = velocity </span>
<span>f = frequency </span>
<span>λ = wavelength (distance between 2 successive crests) </span>

<span>This means that </span>
<span>λ = v/f </span>

<span>Assuming that v stays the same while f increases, λ must DECREASE.

I hope this helps

</span>
4 0
4 years ago
A ball is dropped from rest from a Cliff and falls for 3 seconds.
trasher [3.6K]

Answer:

-29.4 m/s

Explanation:

Given:

v₀ = 0 m/s

t = 3 s

a = -9.8 m/s²

Find: v

v = at + v₀

v = (-9.8 m/s²) (3 s) + (0 m/s)

v = -29.4 m/s

4 0
4 years ago
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