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3 years ago

6

if a band of ribbon is 8 inches long and each inch needs 4 sequins sewn onto it, how many sequins will be needed for the whole r

ibbon

1 answer:

loris [4]3 years ago

3 0

32 because 8 inches x 4 sequins per inch is 32 sequins
Hope i helped

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3. Find the volume of the pyramid.

Gnoma [55]

Answer:

$916.11\:ft^{3}$

Step-by-step explanation:

Volume of the hexagonal pyramid = $1/3\times (area\: of \: hexagonal\:base)\times height$

Here sides of hexagonal base = 9 ft

So, Area of hexagon = $6\times \frac{\sqrt{3} }{4} a^{2}$

$6\times \frac{\sqrt{3} }{4} \times 9 \times 9$

$= 210.5$

Height is given, 13 ft

So, volume = $1/3\times 210.5\times 13$

$= 916.11\: ft^{3}$

<u>OAmalOHopeO</u>

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3 years ago

According to the scale on a map, 1 inch on the map = 15 miles. How many miles are represented by 2.5 inches on the map?

Artyom0805 [142]

2.5 times 15 equals 37.5 miles

7 0

3 years ago

Will give brainlist!!! Please help

damaskus [11]

Answer:

total is (12-4=5(^19 <6>) THIS IS MY ANWER

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2 years ago

How do you solve this question with fractions<br><br> 24 over z + y <br><br> Z and y =6

Viefleur [7K]

24/6+6

24/12

2
I believe the answer is 2

5 0

3 years ago

Read 2 more answers

Fill in Sin, Cos, and tan ratio for angle x. <br> Sin X = 4/5 (28/35 simplified)

Fantom [35]

Answer:

Given: $\sin(x) = (4/5)$ .

Assuming that $0 < x < 90^{\circ}$ , $\cos(x) = (3/5)$ while $\tan(x) = (4/3)$ .

Step-by-step explanation:

By the Pythagorean identity $\sin^{2}(x) + \cos^{2}(x) = 1$ .

Assuming that $0 < x < 90^{\circ}$ , $0 < \cos(x) < 1$ .

Rearrange the Pythagorean identity to find an expression for $\cos(x)$ .

$\cos^{2}(x) = 1 - \sin^{2}(x)$ .

Given that $0 < \cos(x) < 1$ :

$\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}$ .

Hence, $\tan(x)$ would be:

$\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}$ .

7 0

2 years ago