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2 years ago

Return to course

Mathematics

2 answers:

mars1129 [50]2 years ago

8 0

the statement is not true

raketka [301]2 years ago

7 0

Answer:

I think

11cm²-5cm²=121+25

and the square root of that will give you 12.08

and that's the answer

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How often does always never sometimes

Vanyuwa [196]

1) sometimes

2) always

3) always

8 0

1 year ago

Describe a normal probability distribution. a. bell-shaped.b. mean, median, and mode all equivalent.c. bimodal.d. symmetric arou

garri49 [273]

Answer:

a) bell-shaped.

b) mean, median, and mode all equivalent.

d) symmetric around the mean.

g) most of the data fall within 3 standard deviations from the mean.

Step-by-step explanation:

We have to describe a normal distribution.

a. bell-shaped.

This is true a normal distribution is a bell shaped distribution.

b. mean, median, and mode all equivalent.

This is true for a normal distribution.

Mean = Mode = Median

c. Bimodal

The is not true about the normal distribution. A normal distribution is unimodal and the mode is equal to the mean of the distribution.

d. symmetric around the mean.

This is true. The normal distribution is centered around the mean

e. skewed to the right.

This is not a property of normal distribution.

f. models discrete random variables.

Normal distribution is a continuous distribution.

g. most of the data fall within 3 standard deviations from the mean.

This is true. According to Empirical rule, almost all the data lies within three standard deviation of mean.

h. uniform-shaped

This is not true. A normal distribution is bell shaped.

4 0

2 years ago

I need help with these two trigonometry problems.

Sloan [31]

Answer:

$B \approx 32.1\°; A \approx 39.0\°$

Step-by-step explanation:

Sine theorem: in any triangle, the ratio between a side and the sine of the opposite angle is constant

$\frac{sin\ \alpha}a = \frac{sin\ \beta}b =\frac{sin\ \gamma}c$

In our case, for the left triangle,

$\frac {sin\ 103\°}{11} =\frac{sin\ B} 6 \rightarrow sin\ B = \frac6{11} sin\ 103\°$

Time to grab a calculator and crunch numbers. Double check your calculator is in degrees and not in radians (plug in sin 30°, if you're getting 0.5 you're good) and you will get

$sin\ B \approx 0.53 \rightarrow B \approx 32.1\°$

Same difference with the right triangle. With the same calculations

$sin\ A = \frac{26}{41} sin 83\° \approx 0.68 \rightarrow A \approx 39.0\°$

5 0

1 year ago

The house numbers on Carr Memorial Avenue follow a pattern. The first four houses on the left side of the street are numbered 8,

Alinara [238K]

There would be 4 more houses on the left side of the street

3 0

2 years ago

Five classes collected money for a charity of their choice. The amounts of money collected by the boys and girls of each are sho

34kurt

The girls collected 8.5 pounds more than the boys in class 4

<h3>Complete question</h3>

Five classes collected money for a charity of their choice. The amounts of money collected by the boys and girls of each are shown in the chart below.

In Class 4, how much more money did the girls collect than the boys?

<h3>How to determine the difference in amounts?</h3>

From the attached chart, we have the following amount in class 4:

Girls = 12 pounds

Boys = 3.5 pounds

The difference is calculated as:

Difference = Girls - Boys

So, we have:

Difference = 12 pounds - 3.5 pounds

Evaluate

Difference = 8.5 pounds

Hence, the girls collected 8.5 pounds more than the boys in class 4