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2 years ago

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Mathematics

2 answers:

mars1129 [50]2 years ago

8 0

the statement is not true

raketka [301]2 years ago

7 0

Answer:

I think

11cm²-5cm²=121+25

and the square root of that will give you 12.08

and that's the answer

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**WILL GIVE BRAINLIEST** MUST SHOW WORK!

Art [367]

To find the average of an amount of numbers, we simply add them up and divide them by the amount of numbers we have. For example, if we have 1,2, and 3 as our numbers, we can see that we have three numbers. Next, we add them up to get 1+2+3=6. Lastly, we divide 6 by the amount of numbers we have (3) to get 6/3=2 as our average. Applying that here, we see that there are four numbers. Next, we add them up using a calculator to get 5,678.54+3,665.77+4,231.98+4,768.99 =18345.28 . Finally, we divide that number by the amount of numbers we have (using a calculator) to get 18345.28/4=4,586.32, making B your answer.

Feel free to ask further questions, and Happy Halloween!

8 0

2 years ago

Blood pressure values are often reported to the nearest 5 mmHg (100, 105, 110, etc.). The actual blood pressure values for nine

Paladinen [302]

Answer:

a) 117.4

b) 117.9

c) Option A) When there is rounding or grouping, the median can be highly sensitive to small change

Step-by-step explanation:

We are given the following data set in the question:

108.6, 117.4, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

n = 9

a) Median of the reported blood pressure values

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.4, 120.0, 121.5, 123.2, 128.4

Median =

$\dfrac{9 + 1}{2}^{th}\text{ term} = 5^{th}\text{ term} = 117.4$

b) New median of the reported values

Data: 108.6, 117.9, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.9, 120.0, 121.5, 123.2, 128.4

New Median =

$\dfrac{9 + 1}{2}^{th}\text{ term} = 5^{th}\text{ term} = 117.9$

c) Since median is a position based descriptive statistics, a small change in values can bring a change in the median value as the order of the data may change.

Option A) When there is rounding or grouping, the median can be highly sensitive to small change

7 0

2 years ago

20 POINTS!!! Mr. Moore is installing new work benches in the wood shop. He wants the height of the benches to be best for studen

liubo4ka [24]

A: Suppose Mr. Moore decides to use 20 seventh graders as the sample. Is this sample a random sample? Explain your reasoning.

Ans: No, because he only chose the seventh graders which is invalid since he wants to have to use the mean height which involves the 6th, 7th and 8th graders.

B: Mr. Moore decides to use a random number generator to select 20 students from the school. Suppose that when choosing 20 students using the random generator on the graphing calculator, Mr. Moore’s sample is all eighth graders. Does that mean the sample is not a random sample? Explain your reasoning.

Ans: No, it is still a random sample. Since he is using a random generator, there is a possibility that the random generator would pick all students from the 8th grade. Unlike the first one, the random generator is not biased towards any grade, it is just a coincidence.

6 0

3 years ago

Read 2 more answers

If you get a check for $289.25 a week, how much will you have made it at the end of the month

ankoles [38]

1,157 a month has approximate of 4 weeks so
289.25 x 4 = 1,157

4 0

2 years ago

Read 2 more answers

This is due tomorrow and i have answers but i think ive done it wrong! please help

Eva8 [605]

Answer: i) 1 - 9x² - 12x

ii) 17 - 3x²

iii) - 20 + 10x² - x⁴

<u>Step-by-step explanation:</u>

g(x) = 3x + 2 h(x) = 5 - x²

i) h(g(x))

h(3x + 2) = 5 - (3x + 2)²

= 5 - (9x² + 12x + 4)

= 5 - 9x² - 12x - 4

= 1 - 9x² - 12x

ii) g(h(x))

g(5 - x²) = 3(5 - x²) + 2

= 15 - 3x² + 2

= 17 - 3x²

iii) h(h(x))

h(5 - x²) = 5 - (5 - x²)²

= 5 - (25 - 10x² + x⁴)

= 5 - 25 + 10x² - x⁴

= -20 + 10x² - x⁴

4 0

3 years ago