How many moles of sulphur dioxide are produced when 72.0 grams of water is produced by the process: 2H2S + 3O2 --> 2H2O + 2SO
1 answer:
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Density is intensive because it is the ratio of two extensive properties that is mass to volume.
<h3>What is Density ?</h3>Density is defined as mass per unit volume. S.I unit if density is kg/m³.
It is expressed as
Density = or
Intensive property is the property which does not depend on the size of the system. Intensive property can be easily identified. Intensive property is the independent property. The size does not change in this.
Example of intensive property are Density, Freezing point, melting point, colour, Lustre, etc.
<h3>What is Extensive property ?</h3>Extensive property is the property which depend on the substance. Extensive property cannot be easily identified.
Example of extensive property length, weight, volume, mass etc.
Thus from the above conclusion we can say that Density is intensive because it is the ratio of two extensive properties that is mass to volume.
Learn more about Density here: brainly.com/question/1354972
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Question: The density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v)
density = or
Considering that mass and volume are both extensive properties, explain why their ratio, density is intensive.
Answer:
a) The equilibrium will shift in the right direction.
b) The new equilibrium concentrations after reestablishment of the equilibrium :
Explanation:
a) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
On increase in amount of reactant
If the reactant is increased, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where more product formation is taking place. As the number of moles of is increasing .So, the equilibrium will shift in the right direction.
b)
Concentration of = 0.195 M
Concentration of =
Concentration of =
On adding more to 0.370 M at equilibrium :
Initially
0.370 M
At equilibrium:
(0.370-x)M
The equilibrium constant of the reaction =
The equilibrium expression is given as:
On solving for x:
x = 0.0233 M
The new equilibrium concentrations after reestablishment of the equilibrium :