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Vlad [161]
3 years ago
11

What is mass defect? the difference between the mass of the protons and the mass of the neutrons in an atom the difference betwe

en the mass of the nucleus in an atom and the total mass of individual nucleons the difference between the mass of the nucleus of an atom before and after a nuclear reaction
Physics
2 answers:
LuckyWell [14K]3 years ago
8 0

Mass defect is the difference between the mass of the nucleus in an atom and the total mass of individual nucleons.

Mass defect is defined as the difference of mass of nucleus to the sum of masses of proton and neutron.

The mass defect is given by the formula

Δm = (mn +mp)- mo

Here, (mn+mp) -represent combined mass of proton and neutron and mo- denotes original mass of atom

Eddi Din [679]3 years ago
8 0

Answer:

B.

Explanation:

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6 0
4 years ago
The wavelength of 10^15-Hz light is:
Vanyuwa [196]

Answer:

D.300nm

Explanation:

Wavelength = Speed of light / Frequency of light.....

where the speed of light is...(3 × 10^8)

Wavelength = (3 × 10^8)/(1 × 10^15)

Wavelength = 3 × 10^-7

;Wavelength = 300 × 10^-9

Hence its....300 nm

5 0
3 years ago
Impact of electricity in the society
Travka [436]

Answer:

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5 0
2 years ago
The coefficient of static friction between car's tires and a level road is 0.80 If car to be stopped in time of 3.0 sec its spee
Vlad1618 [11]

Answer:

23.5 m/s

Explanation:

The velocity of the car in decelerated motion is given by

v = u + at

where

v = 0 is the final velocity

u is the initial velocity

a is the acceleration of the car

t = 3.0 s is the time it takes for the car to stop

The acceleration of the car is given by the frictional force, which is the only force acting on the car along the direction of motion, so:

ma = -\mu mg\\a = -\mu g = -(0.80)(9.8 m/s^2)=-7.84 m/s^2

where

\mu=0.80 is the coefficient of friction

Solving the previous equation for u, we find the initial velocity:

u=v-at=0-(-7.84 m/s^2)(3.0 s)=23.5 m/s

4 0
4 years ago
An object accelerates downward at a constant rate of 2.00 m/s2 while completely submerged in water. Neglect the viscosity (fluid
Sidana [21]

Answer:

833kg/m³

Explanation:

We have volume as Vm³

Density of this object = dKg/m³

Water density = 1000kg/m³

g = 10m/s²

We calculate FB which is the the buoyant force on object. Calculated as volume of object multiplied by water density

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W = Vdg

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2 = (1000g-gd)/d

2d = 10000 - 10d

2d + 10d = 10000

12d = 10000

d = 833.33kg/m³

Approximately 833kg/m³

The average density of the object is therefore 833kg/m³

5 0
3 years ago
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