Answer:

Explanation:
power through string can be determined as shown in figure

Where
P = 57.3 W
V = 13.87 m/s
H = 567 g/m
we know that


therefore 


Answer:
Work input W = -200.39 KJ
Explanation:
From the question, we are given;
m = 1.15 kg
Constant temperature T1 = T2 = 27 + 273 = 300k
Since the temperature is constant, we can say that the process is isothermal
P1 = 111 KPa
P2 = 0.84 MPa = 0.84 * 1000 KPa = 840 KPa
Now what we want to calculate is W1-2
Mathematically, for isothermal process;
W1-2 = mRTlnP1/P2
where R can be obtained from table and it is equal to 0.287 KJ/kg.k
Hence;
W1-2 = (1.15)(0.287)(300)(ln 111/840)
W1-2 = 99.015 * -2.023871690525 = -200.39 KJ
Kindly note that the value of the work is negative because work is done on the system and not by the system
Kinetic energy = 29.912 J
<h3>Further explanation</h3>
Given
mass = 0.155 kg
vo=initial velocity = 31.4 m/s
h/d=30 m
Required
KE=kinetic energy
Solution
vt²=vo²-2ad⇒vt=final velocity
vt²=31.4²-2.10.30⇒g=10 m/s²
vt²=985.96-600
vt²=385.96 m/s
Kinetic energy (KE)

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