An object of mass m travelling at velocity u collides with an identical stationary object of mass m. After collision, both objec
ts are stick to each other and move together. Find the common final velocity of these objects, v in term of u.
Can someone please help answering the question.
Can someone please help answering the question.
1 answer:
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Answer:
74.86°C
Explanation:
P₂ = Vapour pressure of water at sea level = 760 mmHg
P₁ = Pressure at base camp = 296 mmHg
T₂ = Temperature of water = 373 K
ΔH°vap for H2O = 40.7 kJ/mol = 40700 J/mol
R = Gas constant = 8.314 J/mol K
From Claussius Clapeyron equation
T₁ = 347.996 K = 74.86°C
∴Water will boil at 74.86°C
<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
The speed of a wave is 40 m/s. If the wavelength is 80 centimeters, what is the frequency of the wave ?
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2><h3>Given:-</h3>Velocity (V) = 40 m/s
Wavelength = 80 cm = 0.8 m
The frequency (F) of the wave.
<h2>Solution:-</h2>We know,
40 = F × 0.8
F =
F = 50
<h3>The frequency of the wave is <u>5</u><u>0</u><u> </u><u>H</u><u>z</u>. [Answer]</h3>