An object of mass m travelling at velocity u collides with an identical stationary object of mass m. After collision, both objec
ts are stick to each other and move together. Find the common final velocity of these objects, v in term of u.
Can someone please help answering the question.
Can someone please help answering the question.
1 answer:
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Explanation:
The given data is as follows.
Spring constant (k) = 78 N/m,
Mass of block (m) = 0.50 kg
According to the formula of energy conservation,
mgh sin
h =
=
= 0.64 m
Thus, we can conclude that the distance traveled by the block is 0.64 m.
Answer:
0.000003782 m
0.000001891 m
0.000001197125 m
Explanation:
= Wavelength = 248 nm
D = Diameter of beam = 1 cm
f = Focal length = 0.625 cm
The angle is given by
The width is given by
The required width is 0.000003782 m
Minimum resolvable line separation is given by
The minimum resolvable line separation between adjacent lines is 0.000001891 m
when
The new minimum resolvable line separation between adjacent lines is