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MrMuchimi
3 years ago
13

A rectangular prism is 4 units by 2 1/2 units by 1 1/2 units. How many cubes with a side length of 1/2 unit will completely fill

the prism ?
Mathematics
1 answer:
Keith_Richards [23]3 years ago
3 0
V prism = 4 × (5/2) × (3/2) = 15 units^3;
V cube = (1/2)^3 = 1/8 units^3;
15 ÷ (1/8) = 15 × 8 = 120 cubes;
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Which of the following is a solution of the equation -5x + 2 = -13: answers: x=-9, x=75 x=3 x=-3
slamgirl [31]

Answer:

x= 3

Step-by-step explanation:

1. -5(3) + 2 = -13      

2. -15 + 2 = -13         <em>A positive times a negative will always equal a negative</em>

3. -13 = -13         <em>Whenever you add anything to a negative number, the                    </em>

<em>                            number becomes smaller   </em>

                     Ex:  -10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, ...........

                           <em>Although the number itself becomes smaller, its value    </em>

<em>                             becomes bigger       </em>

Hope this helps.

7 0
3 years ago
Given the functions f(x) = 3x − 1 and g(x) = 3x + 4, which operation results in the smallest coefficient on the x term?
Vera_Pavlovna [14]
Division because if you divide the two functions together, you keep the 3 in the x term. If you add the two functions, your coefficient is 6. If you subtract, the x term is eliminated. If you multiply, you'll get 9x.
3 is smaller than 6 or 9 :)
8 0
3 years ago
Square root of 32 x square root of 1 over 18
lisov135 [29]
<h3>Solution:</h3>

\sqrt{32}  \times  \sqrt{ \frac{1}{18} }  \\  =  \sqrt{32}  \times  \frac{ \sqrt{1} }{ \sqrt{18} }  \\  =  \sqrt{32}  \times  \frac{1}{ \sqrt{18} }  \\  =  \frac{\sqrt{2 \times 2 \times 2 \times 2 \times 2}}{ \sqrt{2 \times 3 \times 3} }   \\  =  \frac{ \sqrt{ {2}^{2}  \times  {2}^{2}  \times 2} }{ \sqrt{2 \times  {3}^{2} } }  \\  =  \frac{2 \times 2 \times  \sqrt{2} }{3 \times  \sqrt{2} }  \\  =  \frac{4 \times  \sqrt{2} }{3 \times  \sqrt{2} }  \\  =  \frac{4}{3}

<h3>Answer:</h3>

\frac{4}{3}

<h3>Hope it helps...</h3>

ray4918 here to help

7 0
2 years ago
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baherus [9]
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4 0
2 years ago
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jenyasd209 [6]

Answer:

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