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ella [17]
3 years ago
10

Electric power companies measure energy consumption in kilowatt-hours, denoted kWh. One kilowatt-hour is the amount of energy tr

ansferred by 1 kW of power in a period of 1 hour. A power company billing statement reports auser's total energy usage to be 1500 kWh. Find the amount of energy in joules used during the billing period.
Physics
1 answer:
Natali [406]3 years ago
7 0

The amount of energy used in the billing period is 5,400,000,000 joules.

One kWH is the amount of energy transferred in one hour, there 1 kWh is equal to

1 kWh=1*1000*(J/s)*3600 s

=3600000 J

Thus the amount of energy in joules consumed by the user for the billing period is =1500*3600000=5,400,000,000 J.

The amount of energy used in the billing period is 5,400,000,000 joules.

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U = R * I \rightarrow U = 10 * 5 = 50 V
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Does the earth have an electric field
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Yes,earth has an electric field

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What is weight if m is mass and g is gravitational force.
Nataly_w [17]
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7 0
3 years ago
Which of the following will cause an induced current in a coil of wire? A. A wire carrying a constant current near the coil B. A
Vika [28.1K]

Answer:

B. A magnet being moved into or out of the coil

Explanation:

Faraday law of electromagnetic induction states that when there is change in flux , an emf is produced . Among the given instances , only in case of B , flux is changing . So current will be induced in the coil . We shall see how it takes place .

A wire carrying constant current will produce magnetic flux in nearby coil but there is no change in flux because current as well as position of wire with respect to coil are  not changing  .

Passing of magnetic field through a stationary coil produces flux in the coil but here too there is no change in flux so no current will be induced .

A magnet positioned near a coil creates magnetic flux in the coil but the magnitude of flux remains constant so no change in flux and no creation of induced current .

7 0
3 years ago
if you throw a rock straight up at a speed of 19m/s. How long goes it take the ball to reach its maximum height?
Scrat [10]

Answer:

It requires <u>1.9 seconds</u> to reach maximum height.

Explanation:

As per given question,  

Initial velocity (U) =19 m/s

Final velocity (V) = 0 m/s

\text { Taking acceleration due to gravity }(a)=10 \mathrm{m} / \mathrm{s}^{2}

Maximum height = S

Time taken is "t"

<u>Calculating time taken to reach maximum height:</u>

We know that time taken to reach the maximum height is calculated by using the formula V = U + at

Substitute the given values in the above equation.

Final velocity is “0” as there is no velocity at the maximum height.

0=19+10 \times t

-19=10 \times t

\frac{-19}{10}=t

t = 1.9 seconds.

The time taken to reach maximum height is <u>1.9</u> seconds.

<u>Calculating maximum height</u>:

\text { Consider the equation } V^{2}-U^{2}=2 a S

Solving the equation we will get the value of S

0-19^{2}=2 \times(-10) \times \mathrm{S} .(-\text { is due to opposite of gravity) }

-361 = -20S

Negative sign cancel both the sides.

\mathrm{S}=\frac{361}{20}

S = 18.05 m

Maximum height is 18.05 m  .

3 0
3 years ago
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