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Ilya [14]
2 years ago
11

Which provides evidence of universe expansion that supports the Big Bang Theory? Select the three correct answers. (2 points)

Physics
1 answer:
baherus [9]2 years ago
3 0

The Big Bang Theory is a theory that describes the origin of the Universe. This theory was first proposed by the Belgian cosmologist G. Lemaitre in 1931.

  • The evidence of universe expansion that supports the Big Bang Theory is the observation that the temperature of the universe is decreasing.

  • According to this theory, the Universe is continuously expanding as it becomes cooler.

The most important lines of evidence that support the Big Bang Theory include:

  1. The observed expansion of the space in the Universe.
  2. The discovery of the cosmic microwave background radiation (CMB) is believed to be leftover radiation from the Big Bang.

Learn more in:

brainly.com/question/9199964?referrer=searchResults

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Long Snorkel: Inhalation of a breath occurs when the muscles surrounding the human lungs move to increase the volume of the lung
Mila [183]

Answer:

h = 0.362 m

Explanation:

The pressure equation with depth is

      P₂ = P_{atm} +ρ g h

The gauge pressure is

       P2 -  P_{atm} = ρ g h

This is the pressure that muscles can create

       P₂ -  P_{atm}= 3740 Pa

But still the person needs a small pressure for the transfer of gases, so

      P₂ -  P_{atm} = 3740 - 188 = 3552 Pa

This is the maximum pressure difference, where the person can still breathe,

Let's clear the height

      h = 3552 / ρ g

      h = 3552 / (1000 9.8)

      h = 0.362 m

This is the maximum depth where the person can still breathe normally.

4 0
3 years ago
A model air rocket with a mass of 50.g is free to travel along a horizontal track. It begins from rest. After 2.0s, the rocket h
katen-ka-za [31]

Answer:

v_r=5.89\ m.s^{-1}

Explanation:

Given:

  • mass of rocket, m_r=50\ g
  • time of observation, t=2\ s
  • mass lost by the rocket by expulsion of air, m_a=10\%\ of m_r=5\ g
  • velocity of air, v_a=53\ m.s^{-1}

<u>Now the momentum of air will be equal to the momentum of rocket in the opposite direction: </u>(Using the theory of elastic collision)

m_a.v_a=(m_r-m_a)\times v_r

5\times 53=(50-5)\times v_r

v_r=5.89\ m.s^{-1}

7 0
3 years ago
Two Polaroids are aligned so that the initially unpolarized light passing through them is a maximum. At what angle should one of
steposvetlana [31]

To solve this problem it is necessary to apply the law of Malus which describes the change in the Intensity of Light when it crosses a polarized surface.

Mathematically the expression is given as

I = I_0 cos^2\theta

Where,

I_0= Initial Intensity

I = Final Intensity after pass through the polarizer

\theta= Angle between the polarizer and the light

Since it is sought to reduce the intensity by half the relationship between the two intensities will be given as

\frac{I}{I_0} = \frac{1}{2}

Using the Malus Law we have,

I = I_0 cos^2\theta

cos^2\theta = \frac{I}{I_0}

cos^2\theta = \frac{1}{2}

\theta = cos^{-1}(\frac{1}{2})^2

\theta = 75.52\°

Angle with respect to maximum is 90-75.52 = 14.48\°

8 0
2 years ago
An electric dipole consisting of charges of magnitude 1.70 nC separated by 6.80 μm is in an electric field of strength 1160 N/C.
bazaltina [42]

Answer:

p = 1.16 10⁻¹⁴ C m     and  ΔU = 2.7 10 -11 J

Explanation:

The dipole moment of a dipole is the product of charges by distance

                        p = 2 a q

With 2a the distance between the charges and the magnitude of the charges

                        p = 1.7 10⁻⁹ 6.8 10⁻⁶

                        p = 1.16 10⁻¹⁴ C m

 

The potential energie dipole  is described by the expression

                       U = - p E cos θ

Where θ is the angle between the dipole and the electric field, the zero value of the potential energy is located for when the dipole is perpendicular to the electric field line

Orientation parallel to the field

                      θ = 0º

                      U = 1.16 10⁻¹⁴ 1160 cos 0

                      U1 = 1.35 10⁻¹¹ J

Antiparallel orientation

                       θ = 180º

                      cos 180 = -1

                      U2 = -1.35 10⁻¹¹ J

The difference in energy between these two configurations is the subtraction of the energies

                         ΔU = | U1 -U2 |

                         ΔU = 1.35 10-11 - (-1.35 10-11)

                         ΔU = 2.7 10 -11 J

6 0
3 years ago
What is the weight of an object with a mass of 19 kg?
Natalija [7]

Answer:

Every 2.2 kg is 1 pound. So mulitply 19 * 2.2. It's gonna be equal to 41.8

Explanation:

7 0
2 years ago
Read 2 more answers
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