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a_sh-v [17]
3 years ago
14

Calculate the speed of a car that has traveled 300 miles in 6 hours.

Physics
1 answer:
PilotLPTM [1.2K]3 years ago
5 0
300 miles / 6 hours = 50 miles per hour
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The crowd at a concert lifts a singer to a height of 2.2 m. The crowd uses a total of force of 600 N. How much work has the crow
nordsb [41]

Answer:

<h2>1320 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 600 × 2.2

We have the final answer as

<h3>1320 J</h3>

Hope this helps you

7 0
3 years ago
vehicles equipped with disc brakes incorporate a mechanically operated drum-style parking brake in the center of the rear disc b
umka21 [38]

Vehicles equipped with disc brakes incorporate a mechanically operated drum-style parking brake in the center of the rear disc brake rotors, commonly called a top hat parking brake.

<h3>What is top hat parking brake?</h3>

The top hat drum style of parking brake system is called the top hat rotors because of how big the middle part is compared to regular rotors.

In this type of parking brake system, the vehicle is equipped with disc brakes which incorporate a mechanically operated drum-style parking brake in the center of the rear disc brake rotors.

Thus, vehicles equipped with disc brakes incorporate a mechanically operated drum-style parking brake in the center of the rear disc brake rotors, commonly called a top hat parking brake.

Learn more about top hat parking brake here: brainly.com/question/21854030

4 0
2 years ago
800 joules of work were done with a force of 200 newtons. Over what
Svetach [21]

Answer:

4m

Explanation:

800/200

7 0
3 years ago
Zero, a hypothetical planet, has a mass of 4.5 x 1023 kg, a radius of 3.2 x 106 m, and no atmosphere. A 10 kg space probe is to
jok3333 [9.3K]

a.) K 2=K 1 +GmM( r 21− r 11)=2.2×10 7J

b.) ​K 2 +GmM( r 11− r 21)=6.9×10 7 J

Applying Law of  Energy conservation :

K 1+U 1

=K 2+U 2

⇒K 1− r 1GmM

=K 2− r 2 GmM

where M=5.0×10 23kg,r1

=> R=3.0×10 6m and m=10kg

(a) If K 1​

=5.0×10 7J and r 2

=4.0×10 6 m, then the above equation leads to

K 2=K 1 +GmM (r 21− r 11)=2.2×10 7J

(b) In this case, we require K 2

=0 and r2

=8.0×10 6m, and solve for K 1:K 1

​=K 2 +GmM (r 11− r 21)=6.9×10 7 J

Learn more about Kinetic energy on:

brainly.com/question/12337396

#SPJ4

7 0
2 years ago
For the equation BaCI2 + Na2SO4 &gt; BaSO4 + 2NaCI
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3 years ago
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