Answer:
120%
Explanation:
Given net sales;
Year 1996 = $690000
Year 1997 = $730000
Year 1998 = $828000
With 1996 as the base year, it means the percentage of any year can be computed by dividing the net sales for that year with the net sales for 1996 and expressing the results as a percentage.
1998 sales as a percentage of the base represents
= $828000/$690000
= 1.2
Expressed as a percentage, this is 120%.
The computation shows that the amount that will be made will be $420.
<h3>How to compute the value?</h3>
From the information, it was stated that a particular plot of land can produce 700 kg of beef per hectare. beef sells for $4/kg.
It was then stated that if that land is converted to producing corn, which sells for $0.15/kg, approximately how much will the farmer make selling corn.
The amount made will be:
= 700 × 4 × 0.15
= 700 × 0.6
= $420
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Answer:
Monopolist profit maximizing price
A: $3 per gallon , total output =270 Kelvins profit = $810(801/7/2 = $405
Maria's profit = $405
B. $2.5 per gallon . Kelvin's profit =$450 Maria's profit = 337.5
C = False. At the same quantity , fall in price brings fall in revenue
Cournot Nash equilibrium
Explanation:
In a monopolist market system , price are set higher than the marginal cost as the producer enjoy the dominance of the market through the production of a unique good.
At the price of $3 , change in demand =(270-225) =45 , change in revenue = ($810-$787.50)22.5 and marginal revenue = (45/22,5) = 0.5. That forms the maximizing price for a monopolist.
On the new arrangement , price drops to $2.5 , Maria's profit =(315-45/2)2.5 = $337.5 and Kelvin's = ($787.5-337.5) = $450
Cournot Nash equilibrium is business model that explains the competition among rival companies producing similar product on the level of output produced independently.
Answer:
EV of node 4 = 0.6×5 + 0.4×0 = 3
EV of node 5 = 0.1×5 + 0.9×0 = 0.5
EV of node 2 = (0.8×5 + 0.2×EV of node 4) - 3
EV of node 2 = (0.8×5 + 0.2×3 ) - 3
EV of node 2 = 4.6 - 3
EV of node 2 = 1.6
EV of node 3 = (0.5×5 + 0.5×EV of node 5) - 1
EV of node 3 = (0.5×5 + 0.5×0.5 ) - 1
EV of node 3 = 2.75 - 1
EV of node 3 = 1.75
EV of node 3 is higher, therefore, best attend pattern is to attend randomly.
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