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erma4kov [3.2K]
3 years ago
9

People who pay attention to detail:

Physics
2 answers:
leonid [27]3 years ago
8 0
The answer to this is option A
Zolol [24]3 years ago
5 0

follow procedures precisely.

apex

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Which statement best compares potential and kinetic energy?. .
Pachacha [2.7K]
The statement that best compares potential and kinetic energy would be : B. only kinetic energy increases when velocity of an object increases

Formula in calculating kinetic energy is : 1/2 m v^2.
which mean as velocity increased, the kinetic energy would be larger

hope this helps
5 0
3 years ago
Read 2 more answers
If a resultant vector is 12 m/s and the horizontal component is 9 m/s, what is the value of the vertical component? A. 5.8 m/s B
horrorfan [7]

The vertical component is B) 7.9 m/s

Explanation:

A vector can be resolved into its horizontal and vertical components. The horizontal and the vertical components form the sides of a right triangle, in which the resultant corresponds to the hypothenuse, so we can use Pythagorean's theorem:

R=\sqrt{R_x^2+R_y^2}

where

R is the resultant vector

Rx is the horizontal component

Ry is the vertical component

In this problem, we have:

R = 12 m/s is the resultant vector

Rx = 9 m/s is the horizontal component

Solving the formula for Ry, we find the vertical component:

R_y = \sqrt{R^2-R_x^2}=\sqrt{12^2-9^2}=7.9 m/s

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

3 0
3 years ago
A parallel-plate capacitor consists of two plates, each with an area of 27 cm^2 separated by 3.0 mm. The charge on the capacitor
aev [14]

Answer:

Explanation:

Capacity of a parallel plate capacitor  C = ε₀ A/ d

ε₀ is permittivity whose value is 8.85 x 10⁻¹² , A is plate area and d is distance between plate.

C =(  8.85 X10⁻¹² X  27 X 10⁻⁴ ) / 3 X 10⁻³

= 79.65 X 10⁻¹³ F.

potential diff between plate = Charge / capacity

= 4.8 X 10⁻⁹ / 79.65 X 10⁻¹³

= 601 V

Electric field = V/d

= 601 / 3 x 10⁻³

= 2 x 10⁵ N/C

Force on proton

= charge x electric field

1.6 x 10⁻¹⁹ x 2 x 10⁵

= 3.2 x 10⁻¹⁴

Acceleration a = force / mass

= 3.2 x 10⁻¹⁴ / 1.67 x 10⁻²⁷

= 1.9 x 10¹³ m s⁻²

Distance travelled by proton = 3 x 10⁻³

3 x 10⁻³ = 1/2 a t²

t = \sqrt{\frac{3\times2\times10^{-3}}{1.9\times10^{13}} }

t = 1.77 x 10⁻⁸ s

6 0
4 years ago
A 5.00-g bullet leaves the muzzle of a rifle with a speed of 320 m/s. the expanding gases behind it exert what force on the bull
muminat

Answer;

= 312 Newtons

Explanation;

The bullet has a mass of 0.005 kg, and a velocity of 320 m/s, so we need to find it's final kinetic energy.  

KE = 1/2*m*v^2

      = 1/2*0.005*320^2

      = 256 Joules.  

Divide this by the distance over which this energy was received and you have the force that provided that energy.  

  = 256/0.820 = 312.195 Newtons  

Rounded off, this is 312 N

3 0
3 years ago
A backyard swimming pool with a circular base of diameter 6.00m is filled to depth 1.50m. (b) Two persons with combined mass 150
Mashutka [201]

The pressure increase at the bottom of the pool after they enter the pool and float is 106.103 Pa.

<h3>What is absolute pressure?</h3>

Absolute pressure is the force that exists in a space when there is no matter present, or when there is a perfect vacuum. This absolute zero serves as the baseline for measurements in absolute pressure. The measurement of barometric pressure is the greatest illustration of an absolute referenced pressure. In order to determine absolute pressure, a complete vacuum is used. In contrast, gauge pressure is the amount of pressure that is measured in relation to atmospheric pressure, also referred to as barometric pressure.

given,

diameter = 6 m

depth = h = 1.5 m

Atmospheric pressure = P₀ = 10⁵ Pa

a) absolute pressure

P = P₀ + ρ g h

P = 10⁵ + 1000 x 10 x 1.5

P = 1.15 x 10⁵ Pa

b) When two person enters into the pool,

mass of the two person = 150 Kg

weight of water level displaced exists equal to the weight of person.

\rho \mathrm{Vg}=2 \mathrm{mg} \\

V=\frac{2 m}{\rho} \\

V=\frac{2 \times 150}{1000} \\

\mathrm{~V}=0.3 \mathrm{~m}^3

Area of pool $=\frac{\pi}{4} d^2$

&=\frac{\pi}{4} \times 6^2 \\

&=28.27 \mathrm{~m}^2

Height of the water rise

h &=\frac{V}{A} \\

h &=\frac{0.3}{28.27} \\

& \mathrm{~h}=0.0106 \mathrm{~m}

  • Pressure increased

P = ρ g h

P = 1000 x 10 x 0.0106

P = 106.103 Pa

To learn more about absolute pressure refer to:

brainly.com/question/17200230

#SPJ4

4 0
2 years ago
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