All categories

3 years ago

What are two factors affecting friction? How do they affect friction? ch

Physics

1 answer:

AlexFokin [52]3 years ago

5 0

The roughness of the surface, the mass of the object, and the area of contact.

You might be interested in

In a shipping yard, a crane operator attaches a cable to a 1240-kg shipping container and then uses the crane to lift the contai

Firdavs [7]

Answer:

Explanation:

Given

mass of ship =1240 kg

height=37 m

(a)Work done by Tension in cable+work done by gravity =0

Work done by gravity =change in potential energy of mass $=-1240\times 9.8\times 37=-449.624 kJ$

Thus work done by tension=449.624 kJ

(b)work done by force of gravity $=-mg\times h=-1240\times 9.8\times 37$ =-449.624 kJ

4 0

3 years ago

Read 2 more answers

Find B when θ=35, E=10V, t=5, N=250, A=1.20m^2

givi [52]

Answer:

its most definitely c. trust me

Explanation:

3 0

2 years ago

Direct current made it possible to distribute electric power over greater areas.

Mademuasel [1]

True, I'm not the best when it comes to science, but I'm pretty sure it's this

3 0

2 years ago

Can someone help me with this?

oksian1 [2.3K]

Answer:

Yes

Explanation:

5 0

2 years ago

Consider a metal single crystal oriented such that the normal to the slip plane and the slip direction are at angles of 60 and 3

Scilla [17]

Explanation:

Given that,

Angle by the normal to the slip α= 60°

Angle by the slip direction with the tensile axis β= 35°

Shear stress = 6.2 MPa

Applied stress = 12 MPa

We need to calculate the shear stress applied at the slip plane

Using formula of shear stress

$\tau=\sigma\cos\alpha\cos\beta$

Put the value into the formula

$\tau=12\cos60\times\cos35$

$\tau=4.91\ MPa$

Since, the shear stress applied at the slip plane is less than the critical resolved shear stress

So, The crystal will not yield.

Now, We need to calculate the applied stress necessary for the crystal to yield

Using formula of stress

$\sigma=\dfrac{\tau_{c}}{\cos\alpha\cos\beta}$

Put the value into the formula

$\sigma=\dfrac{6.2}{\cos60\cos35}$

$\sigma=15.13\ MPa$

Hence, This is the required solution.

3 0

3 years ago