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Lena [83]
3 years ago
13

Which statement best compares potential and kinetic energy?. .

Physics
2 answers:
Pachacha [2.7K]3 years ago
5 0
The statement that best compares potential and kinetic energy would be : B. only kinetic energy increases when velocity of an object increases

Formula in calculating kinetic energy is : 1/2 m v^2.
which mean as velocity increased, the kinetic energy would be larger

hope this helps
Anna007 [38]3 years ago
4 0
Which statement best compares potential and kinetic energy?

Answer: Out of all the options shown above the one that represents the statement that best compares potential and kinetic energy is answer choice B) Only kinetic energy increases when the velocity of an object increases. The reason being that kinetic energy is the energy of any object in motion while potential energy is the stored energy.

I hope it helps, Regards.
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A sprinter runs for 6.45 s at 7.44 m/s. How far does she get?
Gwar [14]

Answer:

D is the answer

Explanation:

6.45×7.44= 47.98800

Which if we round of we get 48m

8 0
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What is the relationship between potential and kinetic energy in chemical reactions?
astraxan [27]

Answer:

2 and 3

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because that's how kinetic and potential energy work

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What force is necessary to accelerate a 50kg box at 30 m/s2?
sammy [17]

Answer:

F = m X a

Therefore ,

Force required = 50 X 30 = 1500 newton

6 0
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A circular loop of flexible iron wire has an initial circumference of 165.0cm, but its circumference is decreasing at a constant
djverab [1.8K]

Answer:

0.005 V

Explanation:

We are given that

Initial circumference of circular loop=C=165 cm

Rate of circumference,\frac{dC}{dt}=12 cm/s

Magnetic field,B=0.5 T

We have to find the induced emf at time t=9 s

We know that induced amf,E=\frac{Bd(A)}{dt}

Area of circular coil,A=\pi r^2

E=B\frac{d(\pi r^2)}{dt}=B(2\pi r)\frac{dr}{dt}

Circumference of circular coil,C=2\pi r

165=2\pi r

r=\frac{165}{2\pi}

\frac{dr}{dt}=\frac{1}{2\pi}\frac{dC}{dt}=\frac{1}{2\pi}\times (12)=\frac{6}{\pi} cm/s=\frac{6\times 10^{-2}}{\pi} m/s

Radius of coil at time t=9 s

r=\frac{165}{2\pi}-(\frac{6}{\pi}\times 9)=9.08 cm=9.08\times 10^{-2} m

1 m=100 cm

E=-0.5(2\pi\times 9.08\times 10^{-2})\times \frac{6\times 10^{-2}}{\pi}=-0.005 V

Magnitude of induced emf=0.005 V

4 0
3 years ago
Read 2 more answers
A graph showing the kinetic energy and speed of a moving object is provided.
ziro4ka [17]

its the 3rd one kinetic energy increases as speed increases

8 0
3 years ago
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